A distance-time graph indicates that an object moves 100 m in 4 s and then remains at rest for 6 s. What is

. Si mi mejor amigo vive a 100 metros de mi casa (una cuadra aproximadamente) y sabe qué cuando pongo una canción determinada es

Damm [24]

Answer:

Nuestro mejor amigo escuchará la música más rápido a una temperatura de 36 ºC (309.15 K)

Explanation:

Supongase que el aire se comporta como un gas ideal y que experimenta un proceso adiabático, entonces la velocidad del sonido ( $v$ ), medida en metros por segundo, queda traducida en la siguiente fórmula:

$v = \sqrt{\frac{\gamma \cdot R_{u}\cdot T}{M} }$ (1)

Donde:

$\gamma$ - Coeficiente de dilatación térmica, sin unidad.

$R_{u}$ - Coeficiente universal de los gases ideales, medido en kilogramo-metros cuadrados por mol-Kelvin-segundo cuadrado.

$T$ - Temperatura, medida en Kelvin.

$M$ - Masa molar, medida en kilogramos por mol.

Como se puede ver, la velocidad del sonido es directamente proporcional a la raíz cuadrada de la temperatura. Por tanto, nuestro mejor amigo escuchará la música más rápido a una temperatura de 36 ºC (309.15 K)

3 0

3 years ago

Two metal plates 15mm apart have a potential difference of 750v between them. The force on a small charged sphere placed between

Romashka [77]

Answer:

50,000 V/m

Explanation:

The electric field between two charged metal plates is uniform.

The relationship between potential difference and electric field strength for a uniform field is given by the equation

$\Delta V=Ed$

where

$\Delta V$ is the potential difference

E is the magnitude of the electric field

d is the distance between the plates

In this problem, we have:

$\Delta V=750 V$ is the potential difference between the plates

d = 15 mm = 0.015 m is the distance between the plates

Therefore, rearranging the equation we find the strength of the electric field:

$E=\frac{\Delta V}{d}=\frac{750}{0.015}=50,000 V/m$

6 0

4 years ago

ANSWER PLEASE FAST I NEED IT

Deffense [45]

14.0.5 cm 13. wind speed surface area temperature

6 0

3 years ago

For an object moving with constant negative acceleration, draw the following:

Tcecarenko [31]

Answer:

Kindly find the graphs attached

Explanation:

For figure 1: There is a steady increase in the position of the object as time increases. This is because despite the negative acceleration (deceleration), the object continues to move and cover more ground as time goes by.

<em>The straight line graph is observed because the acceleration is constant and not varying.</em>

For Figure 2: The graph of velocity vs time will have an inverted nature. This is because since the object is decelerating, it is reducing in its velocity as time goes by (increases). <em>This is also in a straight line since the deceleration is constant.</em>