Answer:
1/3 the distance from the fulcrum
Explanation:
On a balanced seesaw, the torques around the fulcrum calculated on one side and on another side must be equal. This means that:

where
W1 is the weight of the boy
d1 is its distance from the fulcrum
W2 is the weight of his partner
d2 is the distance of the partner from the fulcrum
In this problem, we know that the boy is three times as heavy as his partner, so

If we substitute this into the equation, we find:

and by simplifying:

which means that the boy sits at 1/3 the distance from the fulcrum.
Answer:
0.500 T
Explanation:
Since the change in time and the number of coils are both 1, I set the problem up to be 1.3=(1.5(x)-13(x)). I then plugged in numbers for x until I got the answer to be 1.3 V.
Answer:
i3 =11.014A
i5 = 3.15A
Explanation:
Here according to k'chofs first law
i1 =i2 + i3
i3 = i4 + i5
For determine the i1 you have to consider the resultant resistor of the system
4 , 1 and 3 resistors are in pararel
Then, Resultant is
1/4 + 1/1 + 1/3 = 1/ R
R = 12/19
For get total we have to add another remaining 3 resistor because of serious
Then Resultant is = 12/19 + 3
= 69/19
Then using V = IR
40 =i3* 69/19
i3 = 11.014 A
Other 3 resistors are parrarel because of this voltage of those resistors are same.
Then i inversely propotional to its resistor
Then ,
i5 * 2 = (i3-i5)*4/5
i 5 = 3.15 A
Answer:
1)force:- force is an external affert by any body on an object.
2) force and motion are related to each other. force helps to create motion in any object.
3) frictional force
4) Newton