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Novosadov [1.4K]
2 years ago
9

An engineer is working to design a bouncy ball that conserves all of its kinetic and potential energy. She drops the ball to the

ground from a height of 3 meters. If it really works, how high should the ball bounce
Physics
1 answer:
Finger [1]2 years ago
4 0

If potential energy is conserved or remain the same, the ball will bounce 3 m high.

<h3>Conservation of energy</h3>

The principle of conservation of energy states energy can neither be created nor destroyed  but can be converted from one form to another.

If we apply the principle of conservation of energy, the total potential energy will remain the same.

P.E(initial) = P.E(final)

Thus, If potential energy is conserved or remain the same, the ball will bounce 3 m high.

Learn more about potential energy here: brainly.com/question/1242059

#SPJ4

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2. A brick is sitting on a building 22 m high. It has a mass of 7.9 kg. What amount of potential
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Explanation:

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Mass of brick  = 7.9kg

Height of building  = 22m

Unknown:

Potential energy of the brick  = ?

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The potential energy of a body is the energy at rest of the body. Mathematically;

 

         P.E = mgh

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A mass of 0.5 kg hangs motionless from a vertical spring whose length is 1.10 m and whose unstretched length is 0.50 m. Next the
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Answer:

The maximum length during the motion is L_{max} = 1.45m

Explanation:

From the question we are told that

           The mass  is  m =0.5 kg

            The vertical spring  length is  L = 1.10m

            The unstretched  length is  L_{un} = 1.30m

          The initial speed is v_i = 1.3m/s

          The new length of the spring L_{new} =  1.30 m

The spring constant k is mathematically represented as

                           k = -\frac{F}{y}

Where F is the force applied  = m * g = 0.5 * 9.8=4.9N

           y is the difference in weight which is   =1.10-0.50=0.6m

The negative sign is because the displacement of the spring (i.e its extension occurs against the force F)

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                    k =  \frac{4.9}{0.6}

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The  elastic potential energy is given as E_{PE} = \frac{1}{2} k D^2

  where D is this the is the displacement  

Since Energy is conserved the total elastic potential energy would be

             E_T = initial  \ elastic\ potential \ energy + kinetic \ energy

            E_T = \frac{1}{2} k D_{max}^2 =   \frac{1}{2} k D^2 + \frac{1}{2} mv^2

Substituting value accordingly

                \frac{1}{2} *8.17 *D_{max}^2 =\frac{1}{2} * 8.17*(1.30 - 0.50)^2 + \frac{1}{2} * 0.5 *1.30^2

                4.085 * D_{max}^2 = 3.69

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                D_{max} = 0.950m

So to obtain total length we would add the unstretched length

 So we have

                  L_{max} = 0.950 + 0.5 = 1.45m

                               

               

               

                 

                     

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