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IgorLugansk [536]
3 years ago
11

If the volume of a cylinder is reduced from 8.0 liters to 4.0 liters, the pressure of the gas in the cylinder wil change from 70

kilopascals to what?
Physics
1 answer:
ira [324]3 years ago
4 0
The pressure should increase to 140kPa
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Two balls, one twice as massive as the other, are dropped from the roof of a building (freefall). Just before hitting the ground
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KE= 1/2 mv^2

Kinetic Energy is equal to 1/2 x mass x velocity squared

The mass of the larger ball has TWICE
the kinetic energy. KE is directly proportional to the mass.

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The vector position of an object is given by r what is the torque acting on the object about the origin when a force f = (−12.5i
attashe74 [19]
Let the vector position of the object in the (x-y) plane be 
\vec{r} = x \hat{i} + y \hat{j}

The applied force is
\vec{f} = -12.5 \hat{i}


By definition, the applied torque is
\vec{T} = \vec{r} \times \vec{f} = (x\hat{i} + y\hat{j}) \times (-12.5y \hat{i}) = 12.5\hat{k}

Answer: 12.5y \, \hat{k}

7 0
3 years ago
We are usually not aware of the electric force acting between two everyday objects because
tatuchka [14]

Answer:We are usually not aware of the electric force acting between two everyday objects because most everyday objects have as many plus charges as minus charges. Option A

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A 755 N force is used to push a 15 Kg box across the floor. What is the acceleration of the box?
cluponka [151]

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Explanation:

3 0
2 years ago
Read 2 more answers
When you drink cold water, your body must expend metabolic energy in order to maintain normal body temperature (37° C) by warmi
Gelneren [198K]

Answer:

7.72 Liters

Explanation:

normal body temperature = T_body =37° C

temperature of ice water = T_ice =0°c

specfic heat of water = c_{water} =4186J/kg.°C

if the person drink 1 liter of cold water mass of water is = m = 1.0kg

heat lost by body is Qwater =mc_{water} ΔT

                                           = mc{water} ( T_ice - T_body)

                                             = 1.0×4186× (0 -37)

                                             = -154.882 ×10^3 J

here negative sign indicates the energy lost by body in metabolic process energy expended due to brisk - hour long walk is Q_{walk} = 286 kilocalories

            = 286×4186J

so number of liters of ice water have to drink is

n×Q_{water} =Q_{walk}                                                                        n= Q_{walk}/ Q_{water}

= 286×4186J/154.882×10^3 J

 = 7.72 Liters

7 0
3 years ago
Read 2 more answers
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