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IgorLugansk [536]

4 years ago

11

If the volume of a cylinder is reduced from 8.0 liters to 4.0 liters, the pressure of the gas in the cylinder wil change from 70

kilopascals to what?

1 answer:

ira [324]4 years ago

4 0

The pressure should increase to 140kPa

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A water slide is constructed so that swimmers, starting from rest at the top of the slide, leave the end of the slide traveling

Natalka [10]

Answer:

H = 5 m

Explanation:

As the person leaves the slide horizontally so the time taken by the person to hit the water is given as

$t = 0.672 s$

so we can find the vertical velocity by which person will hit the water using kinematics

$v_y = u_y + at$

$v_y = 0 + (9.81)(0.672)$

$v_y = 6.6 m/s$

now the speed of the person at the end of the slide is given as

$v = \frac{L}{t}$

$v = \frac{5}{0.672}$

$v_x = 7.44 m/s$

now by energy conservation we can find the initial height

$mgH = \frac{1}{2}m(v_x^2 + v_y^2)$

$H = \frac{1}{2g}(v_x^2 + v_y^2)$

$H = \frac{1}{2(9.81)}(7.44^2 + 6.6^2)$

$H = 5 m$

6 0

3 years ago

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Why does your weight change on the moon

lorasvet [3.4K]

Answer:

the moon has different gravitational force.

5 0

3 years ago

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HELP FAST PLS asappppp

Likurg_2 [28]

Answer:

(A) Series and Parallel

Explanation:

Circuit Component: These are electrical devices that makes up the circuit. They include, resistors, capacitors, inductors, voltmeters, ammeters, cell/batteries, earth connection, bulb, switch, connecting wire etc.

These component can either be connected in series or in parallel.

(1) Series Connection: This can be refered as end to end connection of electric component.

(2) Paralel Connection: This can be refered as the side to side connection of electric component.

From the question above,

A electric component in a circuit can be combined in series and in parallel.

The right option is (A) Series and Parallel

7 0

3 years ago

Consider two planets of mass m and 2m,

Rzqust [24]

Answer:

Part a)

$\frac{F_1}{F_2} = 10.125$

Part b)

$\frac{v_1}{v_2} = \sqrt{\frac{4.5r}{r}} = 2.12$

Part c)

$\frac{T_1}{T_2} = 9.54$

Explanation:

Part a)

As we know that the gravitational force is given as

$F = \frac{GMm}{r^2}$

so we will have to find the ratio of force on two planets due to star

so here we have

$\frac{F_1}{F_2} = \frac{m_1r_2^2}{m_2r_1^2}$

$\frac{F_1}{F_2} = \frac{m (4.5r)^2}{(2m) r}$

$\frac{F_1}{F_2} = 10.125$

Part b)

Orbital speed is given as

$v = \sqrt{\frac{GM}{r}}$

so the ratio of two orbital speed is given as

$\frac{v_1}{v_2} = \frac{r_2}{r_1}$

$\frac{v_1}{v_2} = \sqrt{\frac{4.5r}{r}} = 2.12$

Part c)

Time period is given as

$T = 2\pi\sqrt{\frac{r^3}{GM}}$

so the ratio of two time period is given as

$\frac{T_1}{T_2} = \sqrt{\frac{r_1^3}{r_2^3}}$

$\frac{T_1}{T_2} = \sqrt{\frac{4.5r^3}{r^3}}$

$\frac{T_1}{T_2} = 9.54$

8 0

3 years ago

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Help asap please I will give you 5stars

boyakko [2]

Explanation:

In the parallel combination, the equivalent resistance is given by :

$\dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+....$

4. When three 150 ohms resistors are connected in parallel, the equivalent is given by :

$\dfrac{1}{R}=\dfrac{1}{150}+\dfrac{1}{150}+\dfrac{1}{150}\\\\R=50\ \Omega$

5. Three resistors of 20 ohms, 40 ohms and 100 ohms are connected in parallel, So,

$\dfrac{1}{R}=\dfrac{1}{20}+\dfrac{1}{40}+\dfrac{1}{100}\\\\=11.76\ \Omega$

Hence, this is the required solution.

6 0

3 years ago