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elena55 [62]
3 years ago
13

Fill in the blanks to determine the number of protons and electrons in a nitrogen ion. (consult the periodic table to determine

the number of protons in a neutral nitrogen atom.)the n3− ion has _____ protons and _____ electrons.
Chemistry
2 answers:
Stolb23 [73]3 years ago
5 0

Answer:- 7 protons and 10 electrons.

Solution:- Atomic number for nitrogen atom is 7.

For neutral atom, atomic number = number of protons = number of electrons

An ion is formed if electrons are lost or gained by the neutral atom. Here we have nitride ion where nitrogen has -3 charge. This negative 3 charge indicates the gain of 3 electrons by nitrogen atom. The number of protons remains unchanged, means there are still 7 protons.

electrons for the given ion = 7 + 3 = 10

So, N^-^3 ion has 7 protons and 10 electrons.

balandron [24]3 years ago
4 0
7 protons
10 electrons
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CS2 (s) + 3 O2 (g) → CO2 (g) + 2 SO2 (g)
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Answer:

2.067 L ≅ 2.07 L.

Explanation:

  • The balanced equation for the mentioned reaction is:

<em>CS₂(g) + 3O₂(g) → CO₂(g) + 2SO₂(g),</em>

It is clear that 1.0 mole of CS₂ react with 3.0 mole of O₂ to produce 1.0 mole of CO₂ and 2.0 moles of SO₂.

  • At STP, 3.6 L of H₂ reacts with (?? L) of oxygen gas:

It is known that at STP: every 1.0 mol of any gas occupies 22.4 L.

<u><em>using cross multiplication:</em></u>

1.0 mol of O₂ represents → 22.4 L.

??? mol of O₂ represents → 3.1 L.

∴ 3.1 L of O₂ represents = (1.0 mol)(3.1 L)/(22.4 L) = 0.1384 mol.

  • To find the no. of moles of SO₂ produced from 3.1 liters (0.1384 mol) of hydrogen:

<u><em>Using cross multiplication:</em></u>

3.0 mol of O₂ produce → 2.0 mol of SO₂, from stichiometry.

0.1384 mol of O₂ produce → ??? mol of SO₂.

∴ The no. of moles of SO₂ = (2.0 mol)(0.1384 mol)/(3.0 mol) = 0.09227 mol.

  • Again, using cross multiplication:

1.0 mol of SO₂ represents → 22.4 L, at STP.

0.09227 mol of SO₂ represents → ??? L.

∴ The no. of liters of SO₂ will be produced = (0.09227 mol)(22.4 L)/(1.0 mol) = 2.067 L ≅ 2.07 L.

8 0
4 years ago
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