<h3>OXIDATION REACTION</h3>
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![\large \sf \underline{Question:}](https://tex.z-dn.net/?f=%20%5Clarge%20%5Csf%20%5Cunderline%7BQuestion%3A%7D)
- What is the product of the oxidation reaction of isopropyl alcohol with sodium hypochlorite?
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![\large \sf \underline{Answer:}](https://tex.z-dn.net/?f=%20%5Clarge%20%5Csf%20%5Cunderline%7BAnswer%3A%7D)
![\qquad \qquad \huge \bold{Ketone}](https://tex.z-dn.net/?f=%20%5Cqquad%20%5Cqquad%20%5Chuge%20%5Cbold%7BKetone%7D)
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![\large \sf \underline{Explanation:}](https://tex.z-dn.net/?f=%20%5Clarge%20%5Csf%20%5Cunderline%7BExplanation%3A%7D)
- The product of the oxidation reaction of isopropyl alcohol with sodium hypochlorite is called ketone.
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Answer:
Synthesis Reaction
Explanation:
Here we see H2 and O2 are being combined H2O. Synthesis reactions are where we see a combination to make a <u>single product</u>.
So here it'd be A + B =AB
2Na(s)+Cl2(g)→2NaCl(s)
Decomposition would be the break down of a compound into 2, the opposite of synthesis.
AB = A + B
2HgO(s)→2Hg(l)+O2(g)
Single replacement is where 1 element replaces another in a reaction, or switches place with 1 element.
AY + B = A + BY
2 HCl(aq) + Zn(s) → ZnCl2(aq) + H2(g)
Double replacement is similar but 2 elements are switch/replaced.
AY + BX = AX + BY
CuCl2(aq) + 2 AgNO3(aq) → Cu(NO3)2(aq) + 2 AgCl(s)
Answer : The specific heat of tungsten is, ![0.139J/g^oC](https://tex.z-dn.net/?f=0.139J%2Fg%5EoC)
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
![q_1=-q_2](https://tex.z-dn.net/?f=q_1%3D-q_2)
![m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_f-T_1%29%3D-m_2%5Ctimes%20c_2%5Ctimes%20%28T_f-T_2%29)
where,
= specific heat of tungsten = ?
= specific heat of water = ![4.18J/g^oC](https://tex.z-dn.net/?f=4.18J%2Fg%5EoC)
= mass of tungsten = 19.5 g
= mass of water = 78.5 g
= final temperature = ![23.20^oC](https://tex.z-dn.net/?f=23.20%5EoC)
= initial temperature of tungsten = ![97.80^oC](https://tex.z-dn.net/?f=97.80%5EoC)
= initial temperature of water = ![22.58^oC](https://tex.z-dn.net/?f=22.58%5EoC)
Now put all the given values in the above formula, we get
![19.5g\times c_1\times (23.20-97.80)^oC=-78.5g\times 4.18J/g^oC\times (23.20-22.58)^oC](https://tex.z-dn.net/?f=19.5g%5Ctimes%20c_1%5Ctimes%20%2823.20-97.80%29%5EoC%3D-78.5g%5Ctimes%204.18J%2Fg%5EoC%5Ctimes%20%2823.20-22.58%29%5EoC)
![c_1=0.139J/g^oC](https://tex.z-dn.net/?f=c_1%3D0.139J%2Fg%5EoC)
Therefore, the specific heat of tungsten is, ![0.139J/g^oC](https://tex.z-dn.net/?f=0.139J%2Fg%5EoC)
Answer:
<u>The pressure inside becomes : 202.646 KPa</u>
Explanation:
Given ,
- <em>The temperature inside the cylinder is constant</em>
- <em>The number of moles of the gas inside the cylinder will also be constant because it's a closed one.</em>
<em>Now according Boyle's law , </em>
- <em>The pressure of a gas of fixed mass is inversely proportional to its volume at a constant temperature.</em>
Thus ,
![P_1V_1=P_2V_2\\](https://tex.z-dn.net/?f=P_1V_1%3DP_2V_2%5C%5C)
is the initial pressure ![7.257*102*10^3 Pa](https://tex.z-dn.net/?f=7.257%2A102%2A10%5E3%20Pa)
is what we need to find
- initial volume
- final volume
∴
![7.527*102*10^3*12.49=P_2*47.32\\P_2=2.02646*10^5Pa](https://tex.z-dn.net/?f=7.527%2A102%2A10%5E3%2A12.49%3DP_2%2A47.32%5C%5CP_2%3D2.02646%2A10%5E5Pa)
The pressure inside becomes : 202.646 KPa