Configuration of carbon is 1s2 2s2 2p2 and the rest of all is correct
The molarity of the zinc chloride solution will be 0.089 M
<h3>Molarity</h3>
Mole of 7.24 g ZnCl2 = 7.24/136.286 = 0.5312 mol
Total volume of water used in preparing the solution = 300 + 300 = 600 mL
Molarity of the solution = mole/volume = 0.5312/0.6 = 0.089 M
The molarity of the zinc chloride solution is, therefore, 0.089 M
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If there are 2 electrons in the same orbital, the spin numbers would be different for both of these 2 electrons. One would have an up spin and the other a down spin.
Answer:
838 torr
Step-by-step explanation:
To solve this problem, we can use the <em>Combined Gas Laws</em>:
p₁V₁/T₁ = p₂V₂/T₂ Multiply each side by T₁
p₁V₁ = p₂V₂ × T₁/T₂ Divide each side by V₁
p₁ = p₂ × V₂/V₁ × T₁/T₂
<em>Data:
</em>
p₁ = ?; V₁ = 2.42 L; T₁ = 27.0 °C
p₂ = 754 torr; V₂ = 2.37 L; T₂ = -8.8 °C
Calculations:
(a) Convert <em>temperatures to kelvins
</em>
T₁ = (27.0 + 273.15) K = 300.15 K
T₂ = (-8.8 + 273.15) K = 264.35 K
(b) Calculate the<em> pressure
</em>
p₁ = 754 torr × (2.37 L/2.42) × (300.15/264.35)
p₁ = 754 torr × 0.979 × 1.135
p₁ = 838 torr
As we know that the equivalency point of moles of added base will be equal to the moles of original acid, this allows to determine the number of moles of original acid.
<h3>
How do you find the concentration at the first equivalence point?</h3>
At the equivalency point the moles of added base will be equal to the moles of original acid, this allows the determination of the number of moles of original acid. This can be combined with the original volume of the analyte solution in order to determine its concentration.
So we can conclude that at the equivalence point the moles of added base will be equal to the moles of original acid, this allows the determination of the number of moles of original acid.
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