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Y_Kistochka [10]

2 years ago

14

Which is an example of reflection

1 answer:

Elena-2011 [213]2 years ago

5 0

Common examples include the reflection of light, sound and water waves. The law of reflection says that for specular reflection the angle at which the wave is incident on the surface equals the angle at which it is reflected. Mirrors exhibit specular reflection.

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A ball is throw vertically upwards with a speed of 20ms,calculate the maximum height reach(g=10)

Goshia [24]

Please check the attached picture

4 0

2 years ago

A solenoid 91.0 cm long has a radius of 1.50 cm and a winding of 1300 turns; it carries a current of 3.60 A. Calculate the magni

irinina [24]

The magnitude of the magnetic field inside the solenoid is $6.46 \times 10^{-3} \ T$ .

The given parameters;

<em>length of the solenoid, L = 91 cm = 0.91 m</em>
<em>radius of the solenoid, r = 1.5 cm = 0.015 m</em>
<em>number of turns of the solenoid, N = 1300 </em>
<em>current in the solenoid, I = 3.6 A</em>

The magnitude of the magnetic field inside the solenoid is calculated as;

$B = \mu_0 nI\\\\B = \mu_o(\frac{ N}{L} )I\\\\$

where;

$\mu_o$ is the permeability of frees space = 4π x 10⁻⁷ T.m/A

$B = (4\pi \times 10^{-7}) \times (\frac{1300}{0.91} ) \times 3.6\\\\B = 6.46 \times 10^{-3} \ T$

Thus, the magnitude of the magnetic field inside the solenoid is $6.46 \times 10^{-3} \ T$ .

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2 years ago

If we assume that, in the African savanna, the predator population remains constant, what other, nonmobile, factor would influen

musickatia [10]

On usa test prep the answer is c

7 0

3 years ago

Read 2 more answers

Question 3 of 10

Ahat [919]

Answer:

The unit of power is pascal.

3 0

2 years ago

A 0.877-kg ball has an elastic, head-on collision with a second ball that is initially at rest. The second ball moves off with h

Art [367]

Answer: the mass of the second ball is 2.631 kg

Explanation:

Given that;

m1 = 0.877 kg

Initial velocity = V0

Initial momentum = m1 × V0

final velocity of m1 is u1, final velocity of m2 is u2 = v0/2

now final momentum = m1 × u1 + m2 × u2

using momentum conservation;

m1×V0 = m1×u1 + m2×v0/2

m1×(v0 - u1) = m2×V0/2 ----- let this be equation 1

Now, for elastic collision;

m1×v0²/2 = m1×u1²/2 + m2×(v0/2)²/2

m1×(v0² - u1²) = m2×(v0/2)² --------- let this be equation 2

now; equation 2 / equation 1

: V0 + u1 = v0/2

2V0 + 2u1 = V0

2u1 = V0 - 2V0

u1 = -V0/2

now we insert in equ 1

m1×3V0/2= m2×V0/2

m1 × 3 = m2

m2 = 0.877 × 3

m2 = 2.631 kg

Therefore, the mass of the second ball is 2.631 kg

7 0

3 years ago