F = force applied to stop the car = - 3000 N
m = mass of the car = 3000 kg
a = acceleration of the car = ?
v₀ = initial velocity of the car before the force is applied to stop it = 10 m/s
v = final velocity of the car when it comes to stop = 0 m/s
d = stopping distance of the car
acceleration of the car is given as
a = F/m
inserting the values
a = - 3000/3000
a = - 1 m/s²
using the kinematics equation
v² = v²₀ + 2 a d
inserting the values
0² = 10² + 2 (-1) d
0 = 100 - 2 d
2 d = 100
d = 100/2
d = 50 m
hence the correct choice is
C. 50 m
energy never disappears, for example, if you give some kinetic energy to a ball and it stops few seconds later, friction steals this energy to ground which ball was going on. "Law of Conservation of Energy" tell us that energy can't disappear
Then they will most likely slow down unless they do high knees or something like that
Answer:
2.7 m/s²
Explanation:
Average acceleration is change in velocity over change in time. Assuming the acceleration is constant, we can say it is equal to the average:
a = Δv / Δt
a = (6.0 m/s - 0 m/s) / 2.2 s
a ≈ 2.7 m/s²
Answer:
I have made a mistake in my answer
