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butalik [34]
2 years ago
7

The focused, penetrating sound of the koto, which is similar to the tone of Japanese vocal music, comes from the_______________

a. Tension of the stringsc. Relaxation of strings d. Sound wave overlapping d. None of the above
Physics
1 answer:
Arte-miy333 [17]2 years ago
5 0

Answer:

a. Tension of the strings

Explanation:

The koto is a pluckedstring instrument. In these instruments, the sound is obtained causing the vibration in several strings. Therefore, its sound depends on the thickness, extension and tension of the strings. The lower the tension the deeper the sound will be.

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A 06-C charge and a .07-C charge are apart at 3 m apart. What force attracts them?
Andru [333]

Answer:

F = 37.8 × 10^(6) N

Explanation:

The charges are 0.06 C and 0.07 C.

Thus;

Charge 1; q1 = 0.06 C

Charge 2; q2 = 0.07 C

Distance between them; r = 3 m

Formula for the force in between them is;

F = kq1•q2/r²

Where k is a constant = 9 × 10^(9) N.m²/C²

Thus;

F = (9 × 10^(9) × 0.06 × 0.07)/3²

F = 37.8 × 10^(6) N

3 0
3 years ago
Two point charges, initially 2.0 cm apart, experience a 1.0 N force. If they are moved to a new separation of 0.25 cm, what is t
den301095 [7]

Explanation:

Th electric force between charges is inversely proportional to the square of distance between them. It means,

F\propto \dfrac{1}{r^2}

Initial distance, r₁ = 2 cm

Final distance, r₂ = 0.25 cm

Initial force, F₁ = 1 N    

We need to find the electric force between charges if the new separation of 0.25 cm. So,

\dfrac{F_1}{F_2}=(\dfrac{r_2}{r_1})^2\\\\F_2=\dfrac{F_1r_1^2}{r_2^2}\\\\F_2=\dfrac{1\times 2^2}{(0.25)^2}\\\\F_2=64\ N

So, the new force is 64 N if the separation between charges is 64 N.

7 0
3 years ago
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