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Pepsi [2]
3 years ago
11

Visible light travels at a speed 3.0 × 108 of m/s. If red light has a wavelength of 6.5 × 10–7 m, what the frequency of this lig

ht?
A) 2.2 × 10–15 HZ
B) 2.0 × 102 HZ
C) 3.0 × 108 HZ
D) 4.6 × 1014 HZ
Physics
2 answers:
WARRIOR [948]3 years ago
8 0

Answer on Edge is D.

Frequency = (3/6.5) x 10¹⁵ = 0.4615 x 10⁻¹⁵ = 4.615 x 10⁻14 second.

:)

gayaneshka [121]3 years ago
4 0

i think its d on edge

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Is it possible to produce a continuous and oriented aramid fiber–epoxy matrix composite having longitudinal and transverse modul
gregori [183]

Answer:

It is not possible to produce continued and oriented fiber.

Explanation:

To solve the problem it is necessary to take into account the concepts related to Fiber volume ratio. The amount of fiber in a fiber reinforced compound corresponds directly to the mechanical properties of the compound. Given the fiber volume fraction, the theoretical elastic properties of a compound can be determined. The elastic modulus of a compound in the fiber direction of a unidirectional compound can be calculated using the following equation:

E = (1-V_f)E_m+V_fE_f

Where,

E is the longitudinal modulus of Elasticity

V_f is the fiber volume ratio

E_m is the elastic modulus of the matrix

E_f is the elastic modulus of the fibers

We need to consult the table of characteristics of Fibers and Reinforcements of Materials, in which they specify that the modulus of elasticity of the aramid fiber-epoxy is

E_f = 131Gpa

Moreover from the statement,

E = 35Gpa

E_m = 3.4Gpa

Replacing in the previous equation,

35 = 3.4 (1-V_f)+131V_f

V_f = 0.25 \rightarrow longitudinal

To make the comparison we now calculate the Fiber volume ratio through the transverse elastic modulus,

E = \frac{E_mE_f}{(1-V_f)E_f+V_fE_f}

Our values are given in this case as:

E = 5.17Gpa\\E_m = 3.4Gpa \\E_f = 131Gpa

Replacing,

5.17 = \frac{3.4*131}{(1-V_f)(131)+V_f*3.4}

V_f = 0.351 \rightarrow transversal

From both cases it is possible to conclude that it is not possible to produce a fiber of the specified material in a continuous and oriented manner, as long as the volume fraction is different in the different cases.

5 0
3 years ago
A track and field athlete is running forward with a javelin at a
rosijanka [135]

Explanation:

The relative velocity is the velocity of the athlete relative to the ground plus the velocity of the javelin relative to the athlete.

v = 4.2 m/s + 10.3 m/s

v = 14.5 m/s

5 0
3 years ago
2. An auditorium has 58 seats in the first row, 62 seats in the second row, 66 seats in the third row, and so
evablogger [386]
The answer is (a) hope it helped!<3






5 0
2 years ago
Each of the two coils has 320 turns. The average radius of the coil is 6 cm. The distance from the center of one coil to the ele
Temka [501]

Answer:

Magnetic field, B=2.39\times 10^{-3}\ T

Explanation:

It is given that,

Number of turns, N = 320

Radius of the coil, r = 6 cm = 0.06 m

The distance from the center of one coil to the electron beam is 3 cm, x = 3 cm = 0.03 m

Current flowing through the coils, I = 0.5 A

We need to find the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils. The magnetic field midway between the coils is given by :

B=\dfrac{\mu_oINr^2}{(x^2+r^2)^{3/2}}

B=\dfrac{4\pi \times 10^{-7}\times 0.5\times 320\times (0.06)^2}{(0.03^2+0.06^2)^{3/2}}

B = 0.00239 T

or

B=2.39\times 10^{-3}\ T

So, the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils is 2.39\times 10^{-3}\ T. Hence, this is the required solution.

7 0
3 years ago
A 0.20 kg mass is oscillating at a small angle from a light string with a period of 0.78 s.
Scorpion4ik [409]

Answer:

L = 15 cm

Explanation:

T = 2π√(L/g)

L = g(T/2π)²

L = 9.8(0.78/2π)²

L = 0.151027... m

L = 15 cm

7 0
3 years ago
Read 2 more answers
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