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Firdavs [7]
3 years ago
12

You are attending a county fair with your friend from your physics class. While walking around the fairgrounds, you discover a n

ew game of skill. A thin rod of mass
M = 0.535 kg and length ℓ = 2.45 m hangs from a friction-free pivot at its upper end as shown in the figure.

The front surface of the rod is covered with Velcro. You are to throw a Velcro-covered ball of mass m = 1.05 kg at the rod in an attempt to make it swing backward and rotate all the way across the top. The ball must stick to the rod at all times after striking it. If you cause the rod to rotate over the top position (that is, rotate 180° opposite of its starting position), you win a stuffed animal. Your friend volunteers to try his luck. He feels that the most torque would be applied to the rod by striking it at its lowest end. While he prepares to aim at the lowest point on the rod, you calculate how fast he must throw the ball to win the stuffed animal with this technique. How fast must he throw the ball to win the stuffed animal?
Physics
1 answer:
Jet001 [13]3 years ago
6 0

Answer:

I have no idea

Explanation:

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a satellite is traveling in a orbit around the earth. what change would cause it to experience more gravitational force from the
never [62]
The correct answer is:
<span>A. orbiting closer to the earths surface. 

In fact, the gravitational force exerted by the Earth on the satellite is
</span>F=G \frac{Mm}{r^2}
<span>where
G is the gravitational constant
M is the Earth mass
m is the satellite mass
r is the distance of the satellite from the Earth's surface

We can see that, if the satellite orbits closer to the Earth's surface, its distance r from the centre of the planet decreases. But when r decreases, F (the gravitational force) increases, so A is the correct answer.</span>
7 0
3 years ago
a car travelling at 50km/h from rest covers a distance of 10km in 40minutes. Calculate the acceleration​
Margarita [4]

Answer:

9.67\cdot 10^{-3}m/s^2

Explanation:

We can solve the problem by using the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

For the car in this problem:

u = 0 (it starts from rest)

v=50 km/h \cdot \frac{1000}{3600}=13.9 m/s is the final velocity

s = 10 km = 10 000 m is the displacement

Solving for a, we find:

a=\frac{v^2-u^2}{2s}=\frac{13.9^2}{2(10000)}=9.67\cdot 10^{-3}m/s^2

7 0
3 years ago
An archer defending a castle is on a 15.5 m high wall. He shoots an arrow straight down at 22.8 m/s. How much time does it take
vazorg [7]

Answer: 1.907

Explanation:

I did the math

3 0
3 years ago
If the only forces acting on a 2.0kg mass are F1 = (3i-8j)N and F2 = (5i+3j)N, what is the magnitude of the acceleration of the
belka [17]

Answer: 4.7m/s²

Explanation:

According to newton's first law,

Force = mass × acceleration

Since we are given more the one force, we will take the resultant of the two vectors.

Mass = 2.0kg

F1+F2 = (3i-8j)+(5i+3j)

Adding component wise, we have;

F1+F2 = 3i+5i-8j+3j

F1+F2 = 8i-5j

Resultant of the sum of the forces will be;

R² = (8i)²+(-5j)²

Since i.i = j.j = 1

R² = 8²+5²

R² = 64+25

R² = 89

R = √89

R = 9.4N

Our resultant force = 9.4N

Substituting in the formula

F = ma

9.4 = 2a

a = 9.4/2

a = 4.7m/s²

Therefore, magnitude of the acceleration of the particle is 4.7m/s²

3 0
3 years ago
Would u rather/content creator or a rap artist
BartSMP [9]

a content creator because if i was a rapper i probably wouldn't make good songs lol

7 0
2 years ago
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