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Natasha_Volkova [10]
3 years ago
7

An adult human is 60 percent water; a third of this water is in extracellular fluid, and 20 percent of extracellular fluid is in

the blood. If a person weighs 200 pounds, the weight of the interstitial fluid bathing that person's cells weighs approximately _______ pounds.
Physics
1 answer:
Yanka [14]3 years ago
5 0

Answer:

32 pounds

Explanation:

The amount of water in the 200 pound person is

200 * 60% = 200*0.6 = 120 pounds

Of the 120 pounds, a third of this is extracellular fluid, the amount of extracellular fluid is

120 / 3 = 40 pounds

20 % of this is in the blood, which amounts to

40 * 20% = 40 * 0.2 = 8 pounds

The rest is interstitial fluid, which is

40 - 8 = 32 pounds

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A cannon ball is fired with an initial velocity of 75 m/s at an angle of 58 degree above the ground. What maximum height will it
KiRa [710]

Answer:

h = 206.4 m

range = 515.9 m

Explanation:

from the question we are given the following:

initial velocity (u) = 75 m/s

angle  above surface = 58 degrees

acceleration due to gravity (g) = 9.8 m/s^{2}

find the maximum height (h) and the horizontal distance

maximum height (h) = \frac{u^{2}sinθ^{2}  }{2g}

h =  \frac{75^{2}sin58^{2}  }{2 x 9.8}

h = 206.4 m              

the horizontal distance here is the range

range = \frac{u^{2}sin2θ }{g}

range = \frac{75^{2}sin(2 x 58) }{9.8}

range = 515.9 m

7 0
3 years ago
A car of mass 1200 kg is traveling at 2 m/s. Then it collides with a heavy boulder in the road. During the collision, the car mo
olga2289 [7]

Answer:

F = 1.6*10⁴ N

Explanation:

Given distance x = 0.15m, mass m = 1200kg, velocity v = 2m/s.

Unknown: force F

Force is given by Newton's law:

(1) F = ma

The average force to stop an object from a velocity will be the same force necessary to accelerate an object from rest to the same velocity.

The distance for an object starting from rest for a constant acceleration is given by:

(2) x=\frac{1}{2}at^2

The velocity for an object starting from rest for a constant acceleration:

(3) v=at

Using equation 2 and 3 to eliminate time t:

(4) x=\frac{1}{2}a\frac{v^2}{a^2}=\frac{v^2}{2a}

Solving equation 4 for the acceleration a:

(5) a=\frac{v^2}{2x}

Using equation1 to solve for the force F:

(6) F=ma=\frac{mv^2}{2x}

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at stop light the truck traviling at 15m/s passes the carb as it starts from rest the truck travels at a constant relatively ,th
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What's the velocity?

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A radar receiver indicates that a pulse return as an echo in 20 μs after it was sent. How far away is the reflecting object? (c
Assoli18 [71]

A radar receiver indicates that a pulse return as an echo in 20 μs after it was sent. The reflecting object would be 3000 m away .

Phenomenon of hearing back our own sound is called an echo. It is due to successive reflection of sound waves from the surfaces or obstacles of large size. To hear an echo, there must be a time gap of 0.1 second in original sound and the reflected sound.

Given

time =  20 μs = 20 * 10^{-6} s

let distance to the reflecting surface be = x

total distance travelled by pulse will be  = 2x

speed = 3.0 × 10^{8} m/s

distance = speed * time

2x = 3.0 × 10^{8} * 20 * 10^{-6}

   x = 3000 m

The reflecting object would be 3000 m away

To learn more about echo here

brainly.com/question/14861578?referrer=searchResults

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5 0
2 years ago
A 28 g bullet pierces a sand bag 29 cm thick. If the initial bullet velocity was 55 m/s and it emerged from the sandbag with 18
Bumek [7]

The correct answer to the question is 130.4 N.

CALCULATION;

The mass of the bullet is given as m = 28 gram = 0. 028 kg.

The initial velocity of the bullet u = 55 m/s

The final velocity of the bullet  v = 18 m/s.

The distance covered by the bullet through the sand bag s = 29 cm.

                                                                                                   = 0.29 m

Let the acceleration of the bullet is a .

From equation of kinematics, we know that-

                                         v^2-u^2=\ 2as

                                        ⇒ a=\ \frac{v^2-u^2}{2s}

                                               =\ \frac{(18)^2-(55)^2}{2\times 0.29}\ m/s^2

                                              =\ -4656.897\ m/s^2

The negative sign is used due to the fact that force is opposing in nature. Its velocity is decreasing with time.

From Newton's second law of motion, we know that net force on a body is equal to the product of mass with acceleration.

Mathematically F = ma.

Hence, the frictional force exerted on the bullet is calculated as -

                                              F = m × a

                                                 = 0.028 × (-4656.897) N

                                                 = -130.4 N                     [ANS]

Here, N ( newton) stands for the unit of force.

8 0
3 years ago
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