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kolbaska11 [484]
3 years ago
11

How can you determine the number of atoms in a mole of a molecular compound

Chemistry
1 answer:
Brilliant_brown [7]3 years ago
7 0
Well if you go to Quiz-let it gives the answer the mass of a mole of compound is determined by adding the atomic masses of the atoms making up the molecules
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What are the other types of particles that make up a water particle?​
Neko [114]

Answer:Well, if you mean atoms, it has 2 Hydrogen atoms and 1 Oxygen.

Explanation:Water is H20 therefore, it has 2 Hydrogen atoms and 1 Oxygen. Water isn't made up of particles, they are made of atoms.

3 0
3 years ago
Read 2 more answers
The solubility of NaCH3CO2 in water is ~1.23 g/mL. What would be the best method for preparing a supersaturated NaCH3CO2 solutio
Len [333]

Answer:

b) add 130 g of NaCH₃CO₂ to 100 mL of H₂O at 80 °C while stirring until all the solid dissolves, then let the solution cool to room temperature.

Explanation:

The solubility of NaCH₃CO₂ in water is ~1.23 g/mL. This means that at room temperature, we can dissolve 1.23 g of solute in 1 mL of water (solvent).

<em>What would be the best method for preparing a supersaturated NaCH₃CO₂ solution?</em>

<em>a) add 130 g of NaCH₃CO₂ to 100 mL of H₂O at room temperature while stirring until all the solid dissolves.</em> NO. At room temperature, in 100 mL of H₂O can only be dissolved 123 g of solute. If we add 130 g of solute, 123 g will dissolve and the rest (7 g) will precipitate. The resulting solution will be saturated.

<em>b) add 130 g of NaCH₃CO₂ to 100 mL of H₂O at 80 °C while stirring until all the solid dissolves, then let the solution cool to room temperature. </em>YES. The solubility of NaCH₃CO₂ at 80 °C is ~1.50g/mL. If we add 130 g of solute at 80 °C and let it slowly cool (and without any perturbation), the resulting solution at room temperature will be supersaturated.

<em>c) add 1.23 g of NaCH₃CO₂ to 200 mL of H₂O at 80 °C while stirring until all the solid dissolves, then let the solution cool to room temperature.</em> NO. If we add 1.23 g of solute to 200 mL of water, the resulting solution will have a concentration of 1.23 g/200 mL = 0.00615 g/mL, which represents an unsaturated solution.

5 0
3 years ago
ANSWERED
gtnhenbr [62]
That’s looks weird to be honest i have no ideas
6 0
3 years ago
Please help me dont just use me for points
JulijaS [17]

Answer:

It's B

Explanation:

A is going to evaporate more quickly causing it to push through the tube to beaker B.

4 0
3 years ago
Someone give me a hand plz​
alina1380 [7]

Answer:

No, they did not live at the same time.

Explanation:

Hope this helps!

5 0
3 years ago
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