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3 years ago

49.5 is what percent of 33?

1 answer:

6 0

49.5/33 x 100= 150%. This is also rather simple to figure out just by looking at the question itself, you can clearly see that 49.5 is 16.5 greater than 33 and that 16.5 is half of 33. Which you can easily figure out from there.

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Write a numerical expression for the verbal expression. the sum of two an four and six times eight

Trava [24]

(2+4+6)*8 hopefully that's what you are looking for

3 0

2 years ago

Select all ratios equivalent to 7:12.<br> 3:36, 49:84, 20:21, 10:30

aliina [53]

49:84 is the only one

6 0

3 years ago

Read 2 more answers

Please help really need to pass

VashaNatasha [74]

First add 5 to right side
$\frac{x}{7} = -4+5 = 1$
Next , to cancel the 7, you need to multiply by 7 on both sides
$x = 1*7 = 7$

8 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Anettt [7]

Answer:

Choice C: approximately 121 green beans will be 13 centimeters or shorter.

Step-by-step explanation:

What's the probability that a green bean from this sale is shorter than 13 centimeters?

Let the length of a green bean be $X$ centimeters.

$X$ follows a normal distribution with

mean $\mu = 11.2$ and
standard deviation $\sigma = 2.1$ .

In other words,

$X\sim \text{N}(11.2, 2.1^{2})$ ,

and the probability in question is $X \le 13$ .

Z-score table approach:

Find the z-score of this measurement:

$\displaystyle z= \frac{x-\mu}{\sigma} = \frac{13-11.2}{2.1} = 0.857143$ . Closest to 0.86.

Look up the z-score in a table. Keep in mind that entries on a typical z-score table gives the probability of the left tail, which is the chance that $Z$ will be less than or equal to the z-score in question. (In case the question is asking for the probability that $Z$ is greater than the z-score, subtract the value from table from 1.)

$P(X\le 13) = P(Z \le 0.857143) \approx 0.8051$ .

"Technology" Approach

Depending on the manufacturer, the steps generally include:

Locate the cumulative probability function (cdf) for normal distributions.
Enter the lower and upper bound. The lower bound shall be a very negative number such as $-10^{9}$ . For the upper bound, enter $13$
Enter the mean and standard deviation (or variance if required).
Evaluate.

For example, on a Texas Instruments TI-84, evaluating $\text{normalcdf})(-1\text{E}99,\;13,\;11.2,\;2.1 )$ gives $0.804317$ .

As a result,

$P(X\le 13) = 0.804317$ .

Number of green beans that are shorter than 13 centimeters:

Assume that the length of green beans for sale are independent of each other. The probability that each green bean is shorter than 13 centimeters is constant. As a result, the number of green beans out of 150 that are shorter than 13 centimeters follow a binomial distribution.

Number of trials $n$ : 150.
Probability of success $p$ : 0.804317.

Let $Y$ be the number of green beans out of this 150 that are shorter than 13 centimeters. $Y\sim\text{B}(150,0.804317)$ .

The expected value of a binomial random variable is the product of the number of trials and the probability of success on each trial. In other words,

$E(Y) = n\cdot p = 150 \times 0.804317 = 120.648\approx 121$

The expected number of green beans out of this 150 that are shorter than 13 centimeters will thus be approximately 121.

7 0

3 years ago

A painter worked for 5 hours. He spent 25% of his time painting the kitchen,

il63 [147K]

Answer:

a) 1 hours and 25 minutes

b) 2 hours and 25 minutes

c) 1 hour

d) 30 minutes

Step-by-step explanation:

25/ 100 out of 5 = 1.25

45/100 out of 5 = 2.25

20/100 out of 5 = 1

10/100 of 5 = .5

8 0

3 years ago