Question

How many iron atoms are in 0.32 mol of Fe2031? 3.9x 1023 jron atoms O 3.9 iron atoms O 6.02 x 1023 iron atoms 1.9 x 1023 iron atoms O 11x 10-24 iron atoms

Answer 1

Answer: $3.9\times 10^{23}$ iron atoms

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

$1 molecule of [tex]Fe_2O_3$ contains= 2 atoms of iron

$1 mole of [tex]Fe_2O_3$ contains=$2\times 6.023\times 10^{23}=12.05\times 10^{23}$  atoms of iron

thus 0.32 moles of $Fe_2O_3$ contains=$\frac{12.05\times 10^{23}}{1}\times 0.32=3.9\times 10^{23}$  atoms  of iron

Thus the sample would have $3.9\times 10^{23}$ iron atoms.