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3 years ago

9

The early universe was composed mainly of which two elements? hydrogen and helium carbon and oxygen hydrogen and oxygen carbon a

nd iron

2 answers:

mrs_skeptik [129]3 years ago

7 0

It took 380,000 years for electrons to be trapped in orbits around nuclei, forming the first atoms. These were mainly helium and hydrogen, which are still by far the most abundant elements in the universe.

Hope this will help you.

Pepsi [2]3 years ago

3 0

Answer:

c.

Hydrogen and Helium

Explanation:

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A sample of a compound contains 0.300 mol of carbon and 1.20 mol of hydrogen. What is the empirical formula of the comp

Margarita [4]

Answer:

CH4

Explanation:

The number of moles of carbon and hydrogen has been given as follows:

C = 0.300 mol

H = 1.20 mol

Next, we divide each mole value by the smallest (0.300)

C = 0.300 ÷ 0.300 = 1

H = 1.20 ÷ 0.300 = 4

The empirical ratio of Carbon and Hydrogen is 1:4, hence, the empirical formula is CH4

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3 years ago

To protect yourself from consuming too much _____, you should limit your consumption of swordfish, king mackerel, and shark. a.

Serggg [28]

Answer:

b. mercury

Explanation:

Fishes and some other sea foods are are known to concentrate mercury in their bodies. Consumption of these products gradually accumulate mercury in the body over time.

More specifically, fishes like swordfish, king mackerel and shark are known to concentrate higher amount of mercury than other species of fishes. Hence, limiting their consumption will protect humans from mercury poisoning.

The correct option is b.

5 0

2 years ago

Read 2 more answers

What is the name of the ionic compound AlBr3?

Aleksandr [31]

Answer: Correct name will be is aluminum bromide

Explanation:

In a molecular formula , $AlBr_3$

Aluminium atoms present = 1

Bromine atoms present = 3

Charge on aluminium is +3 and charge on bromine is -1.

While naming:

Name of the cation is written first. Simple name of the element is written
After name of cation name of an anions written with suffix 'ide' in the end.

So, the name of $AlBr_3$ will be aluminium bromide.

7 0

3 years ago

Read 2 more answers

A 25.0 mL aliquot of 0.0680 M EDTA was added to a 59.0 mL solution containing an unknown concentration of V3 . All of the V3 pre

givi [52]

Answer:

$\mathbf{0.02 M}$

Explanation:

$\text{So, from the given question:}$

$\text{EDTA will make complex with}$ $V^{+3}$ $\text{and the remaining EDTA will react with }$ $Ga^{+3}$

$\text{Hence, the total concentration of}$ $V^{+3}$ & $Ga^{+3}$ $\text{will be equivalent to EDTA concentration.}$

$V_{EDTA} = 25 \ mL$

$V_{V^{+3}} = 59.0 \ mL$

$V_{Ga^{+3}} = 13.0 \ mL$

$M_{EDTA} = 0.0680 \ M$

$M_{V^{+3}} = ???(unknown)$

$M_{Ga^{+3}} = 0.0400 \ M$

$V^{+3} + EDTA \to V[EDTA] + EDTA(Excess) \to^{CoA} \ Ga[EDTA] _{complex}$

$M_{EDTA} \times V_{EDTA} = ( V_{V^+3}\times M_{V^{+3}}+ V_{Ga^{+3} }\times M_{Ga^{+3}}})$

$0.0680 \times 25 = (59\times x + 13 \times 0.040) \\ \\ 1.7 = 59x + 0.52\\ \\ 1.7 - 0.52 = 59x \\ \\ 59x = 1.18$

$x = \dfrac{1.18}{59}$

$\mathbf{x =0.02 \ M }$

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3 years ago

Isopropyl alcohol is a clear liquid with a density of 0.78 g/cm3. If the same small sphere (with a density of 0.88 g/cm3) is dro

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3 years ago