B, C. Also literally a quick search yielded these results, roughly half the time to type this out.
2Fe(s) + O2 -> 2FeO(s)
<span>2 'Fe' atoms on both sides </span>
<span>2 'O' atoms on both sides</span>
The answer is the Second one
Answer:
Option 1 is correct.
The current passing through the brighter bulb is larger.
Explanation:
The brightness of the bulb is determined by the power, I²R
And since they all have equal resistances, the only factor different that could result in more or less power is the current, I through the bulb.
