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Vikentia [17]
3 years ago
10

When during new product development is Design For Manufacture and Assembly (DFMA) most effective? a) At all times b) During prod

uction c) During process design and development d) During product design and development e) Before design
Physics
1 answer:
Lina20 [59]3 years ago
3 0

Answer:most likely E

Explanation:

Why would anybody do something after design there done with there work after that

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The orbital period of an object is 2 x 10^7 and its total radius is 4 x 10^4 m.
SVETLANKA909090 [29]

Answer:

12566

Explanation:

Use formula: vt=2pir/t

7 0
4 years ago
Read 2 more answers
3)A mass of 4 kg rests on a horizontal plane. The plane is gradually inclined until at an angle o=15° with the horizontal, the m
Veronika [31]

Answer:

A mass of 4 Kg rest on the horizontal plane. The plane is gradually inclined until at an angle of θ=15

∘

 with the horizontal,the mass just being to slide what is the coffeficient  of static friction between the block & the surface.

Explanation:

7 0
3 years ago
A ski gondola is connected to the top of a hill by a steel cable of length 620 m and diameter 1.5 cm. As the gondola comes to th
xz_007 [3.2K]

Answer:

(a) 89 m/s

(b) 11000 N

Explanation:

Note that answers are given to 2 significant figures which is what we have in the values in the question.

(a) Speed is given by the ratio of distance to time. In the question, the time given was the time it took the pulse to travel the length of the cable twice. Thus, the distance travelled is twice the length of the cable.

v=\dfrac{2\times 620 \text{ m}}{14\text{ s}} = \dfrac{1240\text{ m}}{14\text{ s}}=88.571428\ldots \text{ m/s}= 89\text{ m/s}

(b) The tension, T, is given by

v =\sqrt{\dfrac{T}{\mu}}

where v is the speed, T is the tension and \mu is the mass per unit length.

Hence,

T = \mu\cdot v^{2}

To determine \mu, we need to know the mass of the cable. We use the density formula:

\rho = \dfrac{m}{V}

where m is the mass and V is the volume.

m=\rho\cdot V

If the length is denoted by l, then

\mu = \dfrac{m}{l} = \dfrac{\rho\cdot V}{l}

T = \dfrac{\rho\cdot V}{l} v^{2}

The density of steel = 8050 kg/m3

The cable is approximately a cylinder with diameter 1.5 cm and length or height of 620 m. Its volume is

V = \pi \dfrac{d^{2}}{4} l

T = \dfrac{\rho\cdot\pi d^2 l}{4l}v^2 = \dfrac{\rho\cdot\pi d^2}{4}v^2

T = \dfrac{8050\times\pi\times0.015^2}{4} \times 88.57^2

T = 11159.4186\ldots \text{ N} = 11000 \text{ N}

4 0
4 years ago
An electron is released from rest at a distance of 0.570 m from a large insulating sheet of charge that has uniform surface char
Lelu [443]

Explanation:

Formula to calculate the electric field of the sheet is as follows.

          E = \frac{\sigma}{2 \epsilon_{o}}

And, expression for magnitude of force exerted on the electron is as follows.

            F = Eq

So, work done by the force on electron is as follows.

           W = Fs

where,     s = distance of electron from its initial position

                  = (0.570 - 0.06) m

                  = 0.51 m

First, we will calculate the electric field as follows.

              E = \frac{\sigma}{2 \epsilon_{o}}

                 = \frac{4.60 \times 10^{-12}C/m^{2}}{2 \times 8.854 \times 10^{-12}C^{2}/N m^{2}}

                 = 0.259 N/C

Now, force will be calculated as follows.

                 F = Eq

                    = 0.259 N/C \times 1.6 \times 10^{-19} C

                    = 0.415 \times 10^{-19} N

Now, work done will be as follows.

                    W = Fs

                        = 0.415 \times 10^{-19} N \times 0.51 m

                        = 2.12 \times 10^{-20} J

Thus, we can conclude that work done on the electron by the electric field of the sheet is 2.12 \times 10^{-20} J.

3 0
4 years ago
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Which principle allows us to conclude that gravity acts as the same today and will tomorrow?
Svet_ta [14]

Answer:

Gravity is a constant quantity

Explanation:

4 0
3 years ago
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