To solve this problem we will apply the concept related to the heat transferred to a body to reach a certain temperature. This concept is shaped by the energy ratio of a body which is the product of the mass, its specific heat and the change in temperature. For the specific case, it will be the sum of the heat transferred to the Water, the Aluminum and the loss due to latency due to vaporization in the water. That is to say,
![\Delta Q = m_{Al} C_p \Delta T +m_wC_w \Delta T +m_w L_v](https://tex.z-dn.net/?f=%5CDelta%20Q%20%3D%20m_%7BAl%7D%20C_p%20%5CDelta%20T%20%2Bm_wC_w%20%5CDelta%20T%20%20%2Bm_w%20L_v)
Here,
= Mass of Aluminum
= Specific Heat of Aluminum
= Specific Heat of Water
Mass of water
Latent of Vaporization
Replacing,
![\Delta Q = (0.85)(900)(100-45)+(2)(2000)(100-45)+(0.7)(2258000)](https://tex.z-dn.net/?f=%5CDelta%20Q%20%3D%20%280.85%29%28900%29%28100-45%29%2B%282%29%282000%29%28100-45%29%2B%280.7%29%282258000%29)
Converting,
![\Delta Q = 1842675J (\frac{0.000239006kCal}{1J})](https://tex.z-dn.net/?f=%5CDelta%20Q%20%3D%201842675J%20%28%5Cfrac%7B0.000239006kCal%7D%7B1J%7D%29)
![\Delta Q = 440.409kCal](https://tex.z-dn.net/?f=%5CDelta%20Q%20%3D%20440.409kCal)
Therefore is required 440.409kCal
Working displayed in the picture below, the answer is -11 m s^-2
Answer:
I don't really know but i have an idea
Explanation:
so acceleration means: increase in the rate or speed of something.
so just a head start.
your welcome!!
Answer:
recall that heat absorbed released is given by
Q = mc*(T2 - T1)
where
m = mass (in g)
c = specific heat capacity (in J/g-k)
T = temperature (in C or K)
*note: Q is (+) when heat is absorbed and (-) when heat is released.
substituting,
Q = (480)*(0.97)*(234 - 22)
Q = 98707 J = 98.7 kJ
Explanation:
Answer:
3000 hurs
Explanation: just divide 150000 by 50 and get 3000