Answer:
117.3 W is being removed.
Explanation:
The heat removed can be calculated as:
Q = m*c*ΔT
Where m is the mass, c is the specific heat and ΔT is the temperature variation. Because there're two components:
Q = mwater*cwater*ΔT + maluminum*caluminum*ΔT
Q = (mwater*cwater + maluminum*caluminum)*ΔT
Searching in a thermodynamic table:
cwater = 4.184 J/g°C
caluminium = 0.9 J/g°C
In 1 minute, the temperature decreases 2.2°C, so ΔT = -2.2°C
Q = (700*4.184 + 300*0.9) * (-2.2)
Q = -7037.36 J
The rate of energy is the potency (P), which is the heat divided by the time. So, for 1 minute (60 s):
P = -7037.36/60
P = -117.3 J/s
P = -117.3 W
The minus signal indicates that the energy is being removed.
to solve the amount of sulfuric acid to maximize the profit
we need to establish the profit
let S(x) = 100x the selling price
P = S(x) – C(x)
P = 100x – ( 100,000 + 50x + 0.0025x^2)
P = 50x – 100000 – 0.0025x^2
Getting the first derivative and equating it to 0
0 = 50 – 0.005x
X = 10000 units of sulfuric acid
But the capacity is only 7000 units
<span>So 7000 units should be manufactured</span>
In the reduction-oxidation reaction given, Cu is reduced because it gained 2 electrons, on the other hand H2 is oxidized because it gained one electron. I hope this helps.
Molecules of water in the ocean
