All categories

2 years ago

The compound sodium thiosulfate pentahydrate, Na2S2O3 • 5H2O

Chemistry

1 answer:

Mnenie [13.5K]2 years ago

4 0

The theoretical yield is 204.4 g while the percent yield is 2.57%.

<h3>What is theoretical yield?</h3>

Theoretical yield is the amount of product obtained based on the stoichiometry of the reaction.

S8(s) + 8 Na2SO3(aq) + 40 H2O(l) --->8 Na2S2O3·5 H2O(s)

Number of moles of sulfur = 3.25 g /8(32) = 0.013 moles

Number of moles of sodium sulfite = 13.1 g/126 g/mol = 0.103 moles

Since 1 moles of sulfur reacts with 8 moles of sodium sulfite

0.013 moles reacts with 0.013 moles × 8 moles /1 mole = 0.104 moles

There is not enough sodium sulfite hence it is the limiting reactant.

1 mole of sodium sulfite yields 8 moles of product

0.103 moles of sodium sulfite yields 0.103 moles × 8 moles /1 mole = 0.824 moles

Mass of product = 0.824 moles × 248 g/mol = 204.4 g

percent yield = 5.26 g /204.4 g × 100/1

= 2.57%

Learn more about percent yield: brainly.com/question/2506978

You might be interested in

g You observed the formation of several precipitates in the Reactions in Solution lab exercise. Identify the precipitate in each

RUDIKE [14]

<u>Answer:</u>

<u>For a:</u> Lead iodide is a yellow precipitate.

<u>For b:</u> Barium sulfate is a white precipitate.

<u>For c:</u> Ferric hydroxide is a brown precipitate.

<u>For d:</u> Copper (II) hydroxide is a blue precipitate.

<u>Explanation:</u>

Precipitation reaction is defined as the reaction where a solid precipitate (solid substance) is formed at the end of the reaction. It is insoluble in water.

For the given options:

<u>For (a):</u>

The chemical reaction between KI and lead (II) nitrate follows:

$2KI(aq)+Pb(NO_3)_2(aq)\rightarrow PbI_2(s)+2KNO_3(aq)$

The iodide of lead is generally insoluble in water. Thus, lead iodide is a yellow precipitate.

<u>For b:</u>

The chemical reaction between barium chloride and sulfuric acid follows:

$BaCl_2(aq)+H_2SO_4(aq)\rightarrow BaSO_4(s)+2HCl(aq)$

The sulfate of barium is insoluble in water. Thus, barium sulfate is a white precipitate.

<u>For c:</u>

The chemical reaction between NaOH and ferric chloride follows:

$3NaOH(aq)+FeCl_3(aq)\rightarrow Fe(OH)_3(s)+3NaCl(aq)$

The hydroxide of iron is insoluble in water. Thus, ferric hydroxide is a brown precipitate.

<u>For d:</u>

The chemical reaction between NaOH and copper sulfate follows:

$CuSO_4+2NaOH\rightarrow Cu(OH)_2+Na_2SO_4$

The hydroxide of copper is insoluble in water. Thus, copper (II) hydroxide is a blue precipitate.

6 0

3 years ago

1. How much heat is required to melt 25.0 g of ice at 0°C?

tigry1 [53]

Answer: The heat required to melt 25.0 g of ice at $0^0C$ is 8350 Joules

Explanation:

Heat of Fusion tells us how much energy is needed to convert 1g of a solid to a liquid at the same temperature.

$Q=m\times L$

Q = Heat absorbed = ?

m = mass of ice = 25.0 g

L = Latent heat of fusion of ice = 334 J/g

Putting in the values, we get:

$Q=25.0g\times 334J/g=8350J$

Thus heat required to melt 25.0 g of ice at $0^0C$ is 8350 Joules

8 0

3 years ago

How to draw lewis dot structure of BH2-

frosja888 [35]

I am attaching a picture cause I cannot write it directly

Hope it helps
Plz mark as brainliest

6 0

3 years ago

Students were asked to identify the location of elements in the

Naddika [18.5K]

Answer:амьсгал боогдов гэж найдаж байна

Explanation:

4 0

3 years ago

HURRYYY!!!!<br> Convert 7.13 x 10^28 atoms of calcium (Ca) to moles of calcium.

puteri [66]

Answer:

<h2>118,438.5 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L}\\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{7.13 \times {10}^{28} }{6.02 \times {10}^{23} } \\ = 118438.538...$

We have the final answer as

<h3>118,438.5 moles</h3>

Hope this helps you

4 0

3 years ago