We can use a ratio to solve this question. Lets refer to the amount formed by the formula as a serving
1 serving needs 3/8 gal
We want to create 7/9 servings extra, so
1 + 7/9 = 16/7
1 : 3/8
16/7 : x
1/(3/8) = (16/7) / x
8 / 3 = 16x / 7
x = 7/6
He needs to use 7/6 gallons of water.

5 0

3 years ago

An equilibrium mixture of O2, SO2 and SO3 contains equal concentrations of SO2 and SO3.

AleksAgata [21]

Answer:

[O₂(g)] = 0.0037M

Explanation:

2SO₂(g) + O₂(g) => 2SO₃(g)

Conc: [SO₂(g)] [O₂(g)] [SO₃(g)] and [SO₂(g)] = [SO₃(g)]

Kc = [SO₃(g)]²/[O₂(g)][SO₂(g)]² => Kc = 1/[O₂(g)] = 270 if [SO₂(g)] = [SO₃(g)]

∴ [O₂(g)] = (1/270)M = 0.0037M

7 0

3 years ago

g Suppose a sample of an ideal gas in a container is subjected to a temperature change. A decrease in temperature will the kinet

Umnica [9.8K]

Answer:

323.15 °C

Explanation:

Considering the ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Thus, at constant volume and number of moles, Pressure of the gas is directly proportional to the temperature of the gas.

P ∝ T

Also,

Using Charle's law

$\frac {P_1}{T_1}=\frac {P_2}{T_2}$

Given ,

P₂ = 2P₁

T₁ = 25 °C

T₂ = ?

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (25 + 273.15) K = 298.15 K

Using above equation as:

$\frac{P_1}{298.15}=\frac{2P_1}{T_2}$

$T_2=2\times 298.15\ K$

New temperature = 596.3 K

Also,

T(K) - 273.15 = T( °C)

<u>So, Temperature = 596.3 - 273.15 °C = 323.15 °C</u>

5 0

3 years ago