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True [87]
3 years ago
14

Hello people ~(๑¯◡¯๑)how can we separate mercury and water?​

Chemistry
2 answers:
Sindrei [870]3 years ago
8 0

Answer:

Explanation:

Sure you can - Mercury and water are both liquid at room temperature and atmospheric pressure. But Mercury is much much heavier or denser than water. So much that the two substances will not mix.  The lighter water can be separated by pouring it out while the heavy Mercury will stay in the bottom.

NemiM [27]3 years ago
5 0

Do follow the following steps.

  • Take a boul.
  • Add mercury and waters mixture
  • Mix it with help of spoon or glass rod.
  • Mercury is much denser than water so it will sink down.
  • Water remains at top.
  • Now pour water out .

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Dalton’s Law CalculationA mixture of H₂, N₂ and Ar gases is present in a steel cylinder. The total pressure within the cylinder
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Answer:

A) The partial presssure of CO₂ is 167 mm Hg

B) The partial presssure of N₂ is 354 mm Hg

C) The partial presssure of Ar is 235 mm Hg

D) The partial presssure of H₂ is 86 mm Hg

Explanation:

Dalton's law of partial pressures is basically expressed by the following statement:

The total pressure of a mixture is equal to the sum of the partial pressures of its components.

So initially we have:

P_{T}= total presure of the system (675 mm Hg).

P_{N_2}= partial pressure of N₂ (354 mm Hg).

P_{Ar}= partial pressure of Ar (235 mm Hg).

Using Dalton's law we can find the partial pressure of H₂:

P_{T}=P_{N_2}+P_{Ar}+P_{H_2}

675 mm Hg=354 mm Hg + 235 mm Hg + P_{H_2}

P_{H_2}= 675 mm Hg - 354 mm Hg - 235 mm Hg

P_{H_2}=86 mm Hg

If CO₂ gas is added to the mixture, at constant temperature, and the volume is the same, the difference between the new total pressure and the previous total pressure is equal to the partial pressure of CO₂.

P_{T}=P_{N_2}+P_{Ar}+P_{H_2}+P_{CO_2}

842 mm Hg= 354 mm Hg + 235 mm Hg + 86 mm Hg + P_{CO_2}

P_{CO_2}= 842 mm Hg - 354 mm Hg - 235 mm Hg - 86 mm Hg

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3 years ago
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