Which statement is true of a concave lens?
2 answers:
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1) D) 10.0 m
To find the average distance between the wave peaks, we can use the formula:
where in this case:
v = 2.5 m/s is the average velocity
d = ? is the average distance
t = 4 s is the time between two wave peaks
Re-arranging the equation, we find
2) B) Power
This is exactly the definition of power. In fact, power is defined as the ratio between the amount of work done / of energy used, and the time taken for this conversion to occur:
where
W is the amount of work done / of energy used
t is the time taken
3) C) The body builder uses the same energy and but more power.
The energy used by the body builder does not change: in fact, it is only related to the height at which he lift the weight. The work done to lift the weight, of mass m, up to a height of h, is given by
where g is the gravitational acceleration. So, this quantity does not change. Instead, the power changes, because the time the body builder takes to lift the weight up has decreased, and the power depends on the time as we know from the formula:
so, since t has decreased, P has increased.
4) D) body mass, final height, and the time required to complete the climb
The power output is given by:
where:
m is the body mass
g is the gravitational acceleration
h is the final height
t is the time required to complete the climb
Therefore, we see that correct choice is D.
Answer:
73.67 m
Explanation:
If projected straight up, we can work in 1 dimension, and we can use the following kinematic equations:
,
Where its our initial height,
our initial speed, a the acceleration and t the time that has passed.
For our problem, the initial height its 0 meters, our initial speed its 38.0 m/s, the acceleration its the gravitational one ( g = 9.8 m/s^2), and the time its uknown.
We can plug this values in our equations, to obtain:
note that the acceleration point downwards, hence the minus sign.
Now, in the highest point, velocity must be zero, so, we can grab our second equation, and write:
and obtain:
Plugin this time on our first equation we find: