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vaieri [72.5K]
3 years ago
8

An airplane was moving 1200 km per minute traveling in a north-to-south direction when they were spotted by air traffic control.

Because they were only 2 miles off the ground and 5 miles away the airplane was contacted for safety concerns.
Which best describes the motion of the airplane?

Its acceleration was 1200 km/s
Its speed was 1200 km/m southward
Its velocity was 20 km/s southward
Its velocity was 20 km/m
Physics
2 answers:
Feliz [49]3 years ago
7 0

Its velocity was 20 km/s southward

bulgar [2K]3 years ago
4 0

Answer:

Its velocity was 20 km/s southward

Explanation:

As we know that airplane is moving from North to South

So here we will have

v = 1200 km/min

now we know

1 min = 60 s

so we will have

v = 1200 \times \frac{1}{60}

v = 20 km/s

so the velocity of the airplane is towards South moving with speed v = 20 km/s so correct answer will be

Its velocity was 20 km/s southward

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Explanation:

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Answer:

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8 0
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In a 350-m race, runner A starts from rest and accelerates at 1.6 m/s^2 for the first 30 m and then runs at constant speed. Runn
kifflom [539]

Answer:

B can take 0.64 sec for the longest nap .

Explanation:

Given that,

Total distance = 350 m

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We need to calculate the time for A

Using equation of motion

s=ut+\dfrac{1}{2}at_{A}^2

Put the value in the equation

30=0+\dfrac{1}{2}\times1.6\times t_{A}^2

t_{A}=\sqrt{\dfrac{30\times2}{1.6}}

t_{A}=6.12\ sec

We need to calculate the time for B

Using equation of motion

s=ut+\dfrac{1}{2}at_{B}^2

Put the value in the equation

30=0+\dfrac{1}{2}\times2.0\times t_{B}^2

t_{B}=\sqrt{\dfrac{30\times2}{2.0}}

t_{B}=5.48\ sec

We need to calculate the time for longest nap

Using formula for difference of time

t'=t_{A}-t_{B}

t'=6.12-5.48

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Hence, B can take 0.64 sec for the longest nap .

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Answer:

ok...

Explanation:

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Calculate velocity at halfway to the ground.

vfinal = root 2ad

v = root (2*9.81m/s^2*25)

v = 69.367175234 m/s

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Ek = 2405.9025 Joules
4 0
2 years ago
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