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svp [43]
3 years ago
15

In simple summary form, the input of the Calvin cycle for every product is __________, and the output is __________ used for glu

cose synthesis. View Available Hint(s) In simple summary form, the input of the Calvin cycle for every product is __________, and the output is __________ used for glucose synthesis.
3 CO2 ...;
a three-carbon molecule 6 CO2 ...;
glucose ADP ... ATP NADP+ ...;
NADPH
Chemistry
1 answer:
Mumz [18]3 years ago
4 0

Answer:

3 CO₂ ......a three-carbon molecule

Explanation:

  • Photosynthesis involves the synthesis of food by green plants and algae in the presence of energy from the sun, water, and carbon dioxide.
  • The process occurs in two stages known as the light-dependent reactions and light-independent reactions also known as the Calvin cycle.
  • During light reactions of photosynthesis, water molecules are split by energy from sunlight to give out oxygen gas and hydrogen ions which are channeled to the Calvin cycle.
  • Additionally, ATP and NADPH molecules are released.
  • In the Calvin cycle, 3 molecules of carbon dioxide are combined with hydrogen ions to yield three carbon-molecules.
  • The process also uses ATP and NADPH from the light reactions.
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How many grams of Na2CO3 are present in 11.8 mL of a solution that is 22.0% Na2CO3 by mass? The density of the solution is 1.10
Sergeeva-Olga [200]

Answer:

The Answer is 2,86 grs Na2CO3

Explanation:

What we have to do is find the mass of Na2CO3 as a pure component or solute. That's because the 11,8 mL are a solution of Na2CO3. This means, the sum between the solute Na2CO3 and water. To find the grams of Na2CO3 as pure component we create a factor series as is shown in the attached file.

Data:

Density of solution (ρ) = 1,10 grs sln Na2CO3/mL sln Na2CO3

Mass Percentage (%) = 22 grs Na2CO3/100 grs sln Na2CO3  

The procedure is explained in the attached file

5 0
2 years ago
BH+ClO4- is a salt formed from the base B (Kb = 1.00e-4) and perchloric acid. It dissociates into BH+, a weak acid, and ClO4-, w
Len [333]

Answer:

The pH of 0.1 M BH⁺ClO₄⁻ solution is <u>5.44</u>

Explanation:

Given: The base dissociation constant: K_{b} = 1 × 10⁻⁴, Concentration of salt: BH⁺ClO₄⁻ = 0.1 M

Also, water dissociation constant: K_{w} = 1 × 10⁻¹⁴

<em><u>The acid dissociation constant </u></em>(K_{a})<em><u> for the weak acid (BH⁺) can be calculated by the equation:</u></em>

K_{a}. K_{b} = K_{w}    

\Rightarrow K_{a} = \frac{K_{w}}{K_{b}}

\Rightarrow K_{a} = \frac{1\times 10^{-14}}{1\times 10^{-4}} = 1\times 10^{-10}

<em><u>Now, the acid dissociation reaction for the weak acid (BH⁺) and the initial concentration and concentration at equilibrium is given as:</u></em>

Reaction involved: BH⁺  +  H₂O  ⇌  B  +  H₃O+

Initial:                     0.1 M                    x         x            

Change:                   -x                      +x       +x

Equilibrium:           0.1 - x                    x         x

<u>The acid dissociation constant: </u>K_{a} = \frac{\left [B \right ] \left [H_{3}O^{+}\right ]}{\left [BH^{+} \right ]} = \frac{(x)(x)}{(0.1 - x)} = \frac{x^{2}}{0.1 - x}

\Rightarrow K_{a} = \frac{x^{2}}{0.1 - x}

\Rightarrow 1\times 10^{-10} = \frac{x^{2}}{0.1 - x}

As, x

\Rightarrow 0.1 - x = 0.1

\therefore 1\times 10^{-10} = \frac{x^{2}}{0.1 }

\Rightarrow x^{2} = (1\times 10^{-10})\times 0.1 = 1\times 10^{-11}

\Rightarrow x = \sqrt{1\times 10^{-11}} = 3.16 \times 10^{-6}

<u>Therefore, the concentration of hydrogen ion: x = 3.6 × 10⁻⁶ M</u>

Now, pH = - ㏒ [H⁺] = - ㏒ (3.6 × 10⁻⁶ M) = 5.44

<u>Therefore, the pH of 0.1 M BH⁺ClO₄⁻ solution is 5.44</u>

5 0
2 years ago
Ap chemistry how to determine if compound is ionic or molecular bqsed on formula
ludmilkaskok [199]
Ionic compound consists of a positively charged ion and a negatively charged anion. For example, NaCl. Na (sodium) is a cation (another word for positively charged ion) and Cl (chloride) is a anion (another way for negatively charged ion.)

Molecular compounds consists of only negatively charged ions. For example Br2I is a compound of 2 elements that are negatively charged.

Unlike ionic compounds, molecular compounds consists of two or more negatively charged elements.  
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Predict how many antacid tablets it would take to produce 120 mL of CO2 gas
Aleksandr [31]
It would take 8 antacid tablets to produce 120 mL of CO2 gas.
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What mass of oxygen gas is consumed in a reaction that produces 4.60 mol sulfur dioxide?
babunello [35]

Answer:

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