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svp [43]
3 years ago
15

In simple summary form, the input of the Calvin cycle for every product is __________, and the output is __________ used for glu

cose synthesis. View Available Hint(s) In simple summary form, the input of the Calvin cycle for every product is __________, and the output is __________ used for glucose synthesis.
3 CO2 ...;
a three-carbon molecule 6 CO2 ...;
glucose ADP ... ATP NADP+ ...;
NADPH
Chemistry
1 answer:
Mumz [18]3 years ago
4 0

Answer:

3 CO₂ ......a three-carbon molecule

Explanation:

  • Photosynthesis involves the synthesis of food by green plants and algae in the presence of energy from the sun, water, and carbon dioxide.
  • The process occurs in two stages known as the light-dependent reactions and light-independent reactions also known as the Calvin cycle.
  • During light reactions of photosynthesis, water molecules are split by energy from sunlight to give out oxygen gas and hydrogen ions which are channeled to the Calvin cycle.
  • Additionally, ATP and NADPH molecules are released.
  • In the Calvin cycle, 3 molecules of carbon dioxide are combined with hydrogen ions to yield three carbon-molecules.
  • The process also uses ATP and NADPH from the light reactions.
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For the reaction ? Fe+? H2o ⇀↽? Fe3o4+? H2 , a maximum of how many grams of fe3o4 could be formed from 354 g of fe and 839 g of
Evgesh-ka [11]

The given reaction is:

3Fe + 4H2O → Fe3O4 + 4H2

Given:

Mass of Fe = 354 g

Mass of H2O = 839 g

Calculation:

Step 1 : Find the limiting reagent

Molar mass of Fe = 56 g/mol

Molar mass of H2O = 18 g/mol

# moles of Fe = mass of Fe/molar mass Fe  = 354/56 = 6.321 moles

# moles of H2O = mass of h2O/molar mass of H2O = 839/18 = 46.611 moles

Since moles of Fe is less than H2O;  Fe is the limiting reagent.

Step 2: Calculate moles of Fe3O4 formed

As per reaction stoichiometry:

3 moles of Fe form 1 mole of Fe3O4

Therefore, 6.321 moles of Fe = 6.321 * 1/ 3 = 2.107 moles of Fe3O4

Step 4: calculate the mass of Fe3O4 formed

Molar mass of Fe3O4 = 232 g/mol

# moles = 2.107 moles

Mass of Fe3O4 = moles * molar mass

= 2.107 moles * 232 g/mol = 488.8 g (489 g approx)

 


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Help me with this question please.​
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