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svp [43]
3 years ago
15

In simple summary form, the input of the Calvin cycle for every product is __________, and the output is __________ used for glu

cose synthesis. View Available Hint(s) In simple summary form, the input of the Calvin cycle for every product is __________, and the output is __________ used for glucose synthesis.
3 CO2 ...;
a three-carbon molecule 6 CO2 ...;
glucose ADP ... ATP NADP+ ...;
NADPH
Chemistry
1 answer:
Mumz [18]3 years ago
4 0

Answer:

3 CO₂ ......a three-carbon molecule

Explanation:

  • Photosynthesis involves the synthesis of food by green plants and algae in the presence of energy from the sun, water, and carbon dioxide.
  • The process occurs in two stages known as the light-dependent reactions and light-independent reactions also known as the Calvin cycle.
  • During light reactions of photosynthesis, water molecules are split by energy from sunlight to give out oxygen gas and hydrogen ions which are channeled to the Calvin cycle.
  • Additionally, ATP and NADPH molecules are released.
  • In the Calvin cycle, 3 molecules of carbon dioxide are combined with hydrogen ions to yield three carbon-molecules.
  • The process also uses ATP and NADPH from the light reactions.
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How many moles of malachite should be formed when 1.5 moles of copper sulphate reacts with an excess of sodium carbonate?
Katen [24]
2 Na₂CO₃ + 2 CuSO₄ + H₂O → CuCO₃.Cu(OH)₂ + 2 Na₂SO₄ + CO₂
Malachite molar mass = 221.1 g / mol
So 2 moles CuSO₄ produce 1 mole of malachite
so 1.5 mole CuSO₄ produce (0.75) mole malachite
Mass of malachite = 0.75 mole * 221.1 g/ mol = 165.83 g 
5 0
3 years ago
What are the 5 phases of matter?
GarryVolchara [31]

Answer:solid

liquid

gas

supercritical fluid

plasma

superfluidity in liquid helium (that is Bose-Einstein condensate property)

supersolidity in fermionic condensate like the potassium40

Hope this helps and i like your profile pic ;)

5 0
3 years ago
It takes 945. kJ/mol to break a nitrogen-nitrogen triple bond. Calculate the maximum wavelength of light for which a nitrogen-ni
kolezko [41]

Answer: 1.274 * 10^ -7 meter (same as 127.4 nanometers

Explanation:

It's given that the energy

required to break the N N triple bond is 945 * 10^3 joules per mole.

One mole contains 6.02 * 10^ 23 molecules, so the energy required per molecule

= 945 * 10^3 / 6.023 * 10^23, or 1.56 * 10^-18 joules.

Then we need a photon whose energy (E) is at least that amount.

The energy E of a photon is related to its frequency f by PLANCK'S EQUATUON,

E = hf,

where h is Planck's constant (6.625 * 10^-34 joule-sec)

and the wavelength w is inversely proportional to the frequency by w = c/f, where c is the speed of light, 2.998 * 10^8 meters per sec.

If h & c are both constants, their product hc is constant, so we can say E = hc/w,

or if we know E and want to find w, a little algebra gives: w = hc/E.

The product hc = 1.9875 * 10^-25 joule-meters,

so w = 1.9875 * 10^-25 / 1.56 * 10^-18, or 1.274 * 10^ -7 meter (same as 127.4 nanometers

6 0
3 years ago
Please help me with these
padilas [110]
<span>The physical layers of the inner core and outer core form a single compositional layer.

</span>
8 0
3 years ago
Acetic acid (HC2H3O2, Ka=1.8x10^-5) is a weak acid. Calculate the pH of an aqueous solution of .25M acetic acid.
tensa zangetsu [6.8K]

Answer: The pH of an aqueous solution of .25M acetic acid is 2.7

Explanation:

HC_2H_3O_2\rightarrow H^+C_2H_3O_2^-

 cM              0             0

c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 0.25 M and \alpha = ?

K_a=1.8\times 10^{-5}

Putting in the values we get:

1.8\times 10^{-5}=\frac{(0.25\times \alpha)^2}{(0.25-0.25\times \alpha)}

(\alpha)=0.0084

[H^+]=c\times \alpha

[H^+]=0.25\times 0.0084=0.0021

Also pH=-log[H^+]

pH=-log[0.0021]=2.7

Thus pH is 2.7

5 0
3 years ago
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