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3 years ago

Solve the below problem.

Chemistry

2 answers:

xz_007 [3.2K]3 years ago

7 0

44.8 I think.. I'm not so smart but I think so.

blagie [28]3 years ago

3 0

the balanced equation for the formation of ammonia is as follows

N₂ + 3H₂ --> 2NH₃

stoichiometry of H₂ to NH₃ is 3:2

in gases number of moles of gas is directly proportional to volume of gases.

therefore molar ratio is equal to volume ratios.

this means volume ratio of H₂ to NH₃ is 3:2

volume of H₂ reacted - 54.1 L

if 3 L of H₂ forms - 2 L of NH₃

then 54.1 L of H₂ forms - 2/3 x 54.1 = 36.1 L of NH₃

volume of NH₃ formed is 36.1 L

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Il See Periodic Table See Hint

zavuch27 [327]

The molecular formula shows the number of atoms present. The molecular formula of the gas is most likely ClO2.

In terms of gas density and molar mass, the ideal gas equation can be written in the form; PM = dRT

Where;

P = pressure of the gas

M = molar mass of the gas

d = density of the gas

R = molar gas constant

T = temperature of the gas

Making the molar mass of the gas the subject of the formula;

M = dRT/P

d = 2.875 g/L

R = 0.082 atmLmol-1K-1

T = 11°C + 273 = 284 K

P = 750.0 mm Hg or 0.99 atm

Substituting values;

M = 2.875 g/L × 0.082 atmLmol-1K-1 × 284 K/ 0.99 atm

M = 67.6 g/mol

The gas is most likely ClO2.

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2 years ago

Below is the word equation for the reaction between sodium hydroxide and hydrochloric acid. Identify the reactant(s) in the reac

Goshia [24]

I a chemical reaction, we have the reactants in the left part,followed by an arrow and then the products.

So, the reactants are the two that are in the left part of the equation:

Sodium hydroxide and Hydrochloric acid

3 0

1 year ago

for a given input force, a ramp increases which of the following? A)height B)output force C)output work D) efficiency

kherson [118]

<span>Answer - C) output work</span>

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4 years ago

A sample consisting of n mol of an ideal gas undergoes a reversible isobaric expansion from volume Vi to volume 3Vi. Find the ch

kolezko [41]

Answer:

The change in entropy of gas is $\Delta S= nC_{P}ln3$

Explanation:

n= Number of moles of gas

Change in entropy of gas = $ds= \int \frac{dQ}{T}$

$dQ= nC_{p}dT$

From the given,

$V_{i}=V$

$V_{f}=3V$

Let "T" be the initial temperature.

$\frac {V_{i}}{T_{i}}=\frac {V_{f}}{T_{f}}$

$\frac {V}{T}=\frac {3V}{T_{f}}$

${T_{f}} = 3T$

$\int ds = \int ^{T_{f}}_{T_{i}} \frac{nC_{P}dT}{T}$

$\Delta S = nC_{p}ln(\frac{T_{f}}{T_{i}})$

$\Delta S = nC_{p}ln3$

Therefore, The change in entropy of gas is $\Delta S= nC_{P}ln3$

3 0

3 years ago

HELP ASAP!!!!!!

blondinia [14]

2, 4, 1

Explanation:

We have the following chemical reaction:

Ag₂O → Ag + O₂

To balance the chemical equation the number of atoms of each element entering the reaction have to be equal to the number of atoms of each element leaving the reaction, in order to conserve the mass.

So the balanced chemical equation is:

2 Ag₂O → 4 Ag + O₂

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6 0

3 years ago