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AysviL [449]
4 years ago
12

How does hess's law use intermediate reactions to calculate the enthalpy of a desired reaction?

Chemistry
2 answers:
Alla [95]4 years ago
8 0

Answer : Hess's law uses the intermediate reactions to calculate the enthalpy by the law of Constant Heat Summation which states that regardless of the multiple stages occurring in the reaction, the total enthalpy change for the reaction is the sum of all changes.

This law was a manifestation that enthalpy is a state function i.e it is irrespective of the path followed to reach the final state.

The application of Hess’s law, uses the standard heats of formation of the reactants and products to indirectly calculate the heat of reaction (enthalpy) for any reaction that occurs at standard conditions.

An enthalpy change which occurs specifically under standard conditions is called the standard enthalpy of reaction and is given the symbol ΔH°.

The standard heat of reaction can be calculated by using the given equation., i.e.;

ΔH° = Σn ΔH°f(products)−ΣnΔH°f(reactants)

Here, Σ represents “the sum of”

The standard heat of reaction is equal to the sum of all the standard heats of formation of the products subtracted by the sum of all the standard heats of formation of the reactants.

The letter “n” represents that each heat of formation must first be multiplied by its coefficient in the balanced equation.

____ [38]4 years ago
7 0
By adding the enthalpies of the intermediate reactions together to get the enthalpy of the desired reaction
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Pure silver has a brilliant white metallic luster. How many moles of silver, Ag, are in 7.54 × 1023 atoms of silver?
AleksAgata [21]

The number of moles of silver, Ag, that are in 7.54 × 10²³ atoms of silver is 1.25 moles

From the question,

We are to determine the number of moles of silver, Ag, that are present in 7.54 × 10²³ atoms of silver

From the formula

Number\ of\ moles  =\frac{Number\ of\ atoms}{Avogadro's\ constant}

Avogadro's  constant = 6.022 × 10²³  atoms mol⁻¹

and

From the given information

Number of silver atoms = 7.54 × 10²³ atoms

Putting the parameters into the formula, we get

Number of moles of silver present = \frac{7.54\times 10^{23} }{6.022\times 10^{23}}

Number of moles of silver present = 1.2520757 moles

Number of moles of silver present ≅ 1.25 moles

Hence, the number of moles of silver, Ag, that are in 7.54 × 10²³ atoms of silver is 1.25 moles

Learn more on calculating number of moles here: brainly.com/question/15839520

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You are given 600 grams of sodium chloride (NaCl), but you are planning to purify the substance and extract just the sodium. How
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236.02 grams of Na is produced by 600g of NaCl.

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