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GrogVix [38]
3 years ago
5

Explain what makes one mineral so precious or costly compared to another.

Chemistry
1 answer:
ValentinkaMS [17]3 years ago
8 0
There are multiple factors that contribute to the cost of a mineral. First of all is the demand or application, which will be related to its physical properties. For example, nontarnishing metals like gold are held in high value for their appearance. Second is the supply of the mineral, those that only have a small quantity in the earth's crust are likely to be more expensive. Third is the cost of extraction and manufacturing. Some minerals may be abundantly found, but may be distributed over a wide area, meaning that it is still expensive to mine and transport.
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How many electrons are in p orbitals in Si (Silicon)?
insens350 [35]

Answer:

6 electrons

Explanation:

The p orbital can hold up to six electrons. We'll put six in the 2p orbital and then put the next two electrons in the 3s.

8 0
3 years ago
At STP, which substance has metallic bonding?
kogti [31]
Silver has metallic bonding.

Silver is a very typical and main metal. The negatively charged electrons distribute themselves throughout the entire piece of metal and form non directional bonds between the positive silver ions, which is metallic bonding, and what silver contributes.
7 0
4 years ago
Read 2 more answers
Please answer number12
densk [106]
Hydrogen maybe but I don’t know for sure
7 0
3 years ago
Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm
8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

\frac{dV}{dt}=10\frac{cm^3}{s}

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

\frac{dh}{dt} = ?*\frac{dV}{dt}

Of course, ?=\frac{dh}{dV}.

Now, since the volume of a cone is V=\pi r^2h/3 and the ratio r/h=15/20=3/4 or r=3/4h, the volume becomes:

V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3

We proceed to its differentiation:

\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}

Then, we compute \frac{dh}{dt}

\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}

Finally, at h=2:

\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}

Best regards.

4 0
3 years ago
A fixed mass of gass occupies a volume of 200cm at 21°c calculate it's volume at standard temperature
elena55 [62]
The answer is in the attachment below:

4 0
2 years ago
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