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ASHA 777 [7]
3 years ago
5

Write a short explanation about the “cheater” way to find the # of valence electrons an element has, and explain what valence el

ectrons have to do with elements bonding?
Chemistry
1 answer:
skelet666 [1.2K]3 years ago
8 0
I don’t know what the “cheater” way is, however you can easily judge how many valence electrons an element has by looking at its group number on the periodic table.

Bonding in chemistry is completely and totally due to electrons. Every element wants 8 electrons in its outer shell in order to be stable. This is what we call the “Octet Rule”.
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6) (a) Calculate the absorbance of the solution if its concentration is 0.0278 M and its molar extinction coefficient is 35.9 L/
Anvisha [2.4K]

Answer:

6) (a) 0.499; (b) 31.7 %

7) 0.15

Explanation:

6) (a) Absorbance

Beer's Law is

A = \epsilon cl\\A = \text{35.9 L&\cdot$mol$^{-1}$cm$^{-1}$} $\times$ 0.0278 mol$\cdot$L$^{-1} \times $ 0.5 cm = \mathbf{0.499}

(b) Percent transmission

A = \log {\left (\dfrac{1}{T}}\right)}\\\\\%T = 100T\\\\T = \dfrac{\%T}{100}\\\\\dfrac{1}{T} = \dfrac{100 }{\%T}\\\\A = \log \left(\dfrac{100 }{\%T} \right ) = 2 - \log \%T\\\\0.499 = 2 - \log \%T\\\\\log \%T = 2 - 0.499 = 1.501\\\\\%T = 10^{1.501} = \mathbf{31.7}

7) Absorbance

A = \log \left (\dfrac{I_{0}}{I} \right ) = \log \left (\dfrac{I_{0}}{0.70I_{0}} \right ) = \log \left (\dfrac{1}{0.70} \right ) = -\log(0.70) = \mathbf{0.15}}

8 0
3 years ago
Barbara is converting 78°F to degrees Celsius. First, she subtracts 32 from 78. What is the next step?
goldfiish [28.3K]

Answer:

Now she multiplies by 0.5556

Explanation:

7 0
2 years ago
How much heat is lost when 575 g of molten iron at 1825 K becomes solid at 1181 K and cools to 293 K?
meriva
Answer is: -963,8 kJ.
Q₁ = m(Fe) · C · ΔT₁.
C - specific heat capacity of liquid iron, C(Fe) = 0,82 J/g°<span>C.
</span>m(Fe) = 575 g.
ΔT₁ = 1181 - 1825 = -644°C.
Q₁ = -859306,5 J = -859,3 kJ.
Q₂ = m(Fe) · C · ΔT₂.
ΔT₂ = 293 - 1181 = -888°C.
C - specific heat capacity, C(Fe) = 0,44 J/g°C.
Q₂ = -224664 J = -224,66 kJ.
Q₃ =- heat of fusion, ΔH = 209 J/g.
Q₃ = 120175 J = 120,17 kJ.
Q = Q₁ + Q₂ + Q₃ = -963,8 kJ.

7 0
3 years ago
Read 2 more answers
What is the molality of a solution of 12.9 g of fructose (C6H12O6) in 31.0 g of water?
jasenka [17]

Answer:

2.31 m C₆H₁₂O₆

Explanation:

Hope this helps

8 0
3 years ago
Question 1 (1 point)
ladessa [460]

Answer:D - adding a catalyst

Explanation:

4 0
3 years ago
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