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lisov135 [29]
3 years ago
11

give an example of motion in which displacement of the particle is zero but acceleration is not zero in journey?

Physics
1 answer:
BartSMP [9]3 years ago
4 0

Motion of a ball thrown by a person upwards and caught after some time is an example of motion in which displacement of the particle is zero but acceleration is not zero in journey.

The displacement of the ball is zero because the starting and end point of the motion are same, i.e, the person's hands.During its motion, the acceleration of ball is constant and non zero called as acceleration due to gravity, g= -9.8 m/s². The velocity of ball is continuously changing. It first decreases during the upward motion of the ball and then increases during the downward journey.The acceleration remains constant and non zero all the time.

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Explain why a moving object cannot come to a stop instantaneously (in zero seconds)
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Answer: The pressure from the air and force of who or what used effort to make it move. For example you roll a ball it doesn't stop unless it runs out of the force which in this case would be energy.

Explanation:

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7 0
3 years ago
You throw a ball downward from a window at a speed of 2.0m/s. How far has it fallen in 3 seconds?
bekas [8.4K]
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a=9.81 m/s^2
Vi= 2 m/s
t= 3 x

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3 0
3 years ago
The redshift of a star means that _____.
Gelneren [198K]
The correct answer is D. the star is getting farther away.

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4 0
3 years ago
Read 2 more answers
The mass of a rocket decreases as it burns through its fuel. If the rocket engine produces constant force (thrust), how does the
Serjik [45]

Answer:

it increases-

Explanation:

When the mass of a rocket decreases as it burns through its fuel and the force ( thrust) is constant then by newtons second law of motion

F= ma  here F is constant this means that   ma= constant

⇒ m= F /a    this implies that mass is inversely proportional to  acceleration.

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6 0
3 years ago
An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid
Katena32 [7]

Answer:

666000000000 J

391764.71 N

Explanation:

u = Initial velocity

v = Final velocity

s = Displacement

Change in energy

\Delta KE=\frac{1}{2}m(v^2-u^2)\\\Rightarrow \Delta KE=\frac{1}{2}3.7\times 10^4(4500^2-7500^2)\\\Rightarrow \Delta KE=-666000000000\ J

Work done be the force is 666000000000 J

W=F\times s\\\Rightarrow F=\frac{W}{s}\\\Rightarrow F=\frac{-666000000000}{1.7\times 10^6}\\\Rightarrow F=-391764.71\ N

The magnitude of force is 391764.71 N

3 0
3 years ago
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