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ddd [48]
2 years ago
9

In the winter activity of tubing, riders slide down snow covered slopes while sitting on large inflated rubber tubes. To get to

the top of the slope, a 2.50 kg tube, is pulled at a constant speed by a tow rope that maintains a constant tension of 12.0 N along the direction of the slope. How much thermal energy is created in the slope and the tube during the ascent of a 6.31-m-high, 52.3-m-long slope, in Joule
Physics
1 answer:
IrinaVladis [17]2 years ago
4 0

Answer:

≈ 473 J

Explanation:

m ( mass ) = 2.5 kg

T ( tension ) = 12 N

v = constant

h ( height ) = 6.31 m

d ( diameter ) = 52.3 m

<u>Determine how much thermal energy is created </u>

considering that external force acts on the system

ΔE = W    and this can be rewritten as

mgh + ΔEth = W --------- ( 1 )

where ΔEth  = amount of thermal energy created

also ; W = Fd cos ∅,  hence Work done by Tension force (w) = Td cos 0 = Td

back to equation ( 1 )

mgh + ΔEth = Td

ΔEth  = Td - mgh

         = ( 12 * 52.3 ) - ( 2.5 * 9.8 * 6.31 )

         ≈ 473 J

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Explanation:

The given data is as follows.

     Velocity of bullet, c_{p} = 814.8 m/s

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                          = 58.66

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The density of a material in CGS system of units is 4g cm-³. In a system of units in which unit of length is 10 cm and unit of m
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\sf\underline{Solution:}

Here , the density of the material is 4g cm³ but it is not given in CGS system.

$\sf{As\:we\:know\:that:}$

$\sf\bold{Density=}$ $\sf\dfrac{Mass}{Volume}$

$\space$

\sf{Now,according \: to \:the\:question:}

$\sf\small{Density\:of\:the\:material=4}$ $\sf\dfrac{g}{cm^2}$

$\space$

$\sf{It\:is\:given\:that:}$

In the system of units the mass is 100gram.

$\space$

Hence,

$\sf{The\:mass\:unit\:for\:4g=}$ $\sf\dfrac{4}{100}$ $\sf{units}$

$\space$

In the system of units,the length is 10cm.

Henceforth,

$\sf\small{The\:length \:for\:1cm\:units=}$ $\sf\dfrac{1}{10}$ $\sf{units}$

$\space$

<u>☆</u><u> </u><u>Substitute</u><u> </u><u>the</u><u> </u><u>required</u><u> </u><u>values</u><u> </u><u>in</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>formula</u><u>-</u>

$\sf\purple{Density=}$ $\sf\dfrac\purple{Mass}\purple{volume}$

$\space$

$\sf\underline\bold{Density\:of\:the\:material:}$

= $\sf\dfrac{4/100}{1/10^3}$ $\sf\bold{units}$

$\space$

= $\sf\dfrac{4/100}{1/1000}$ $\sf\bold{units}$

$\space$

= $\sf\dfrac{4000}{100}$ $\sf\bold{units}$

$\space$

$\sf\underline\bold\blue{=40\:units}$

$\sf\small{Therefore,option\:2nd\:is\:correct!}$

_______________________________

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