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sergey [27]
2 years ago
14

Please help due tomorrow I will give brainliest! and points​

Physics
1 answer:
zhannawk [14.2K]2 years ago
4 0

Answer:

1.) 0.075 km/min

2.) 0 km/min

3.) -0.15 km/min

Explanation:

<u>Formula:</u>

<u />

s= \frac{d}{t}

  • s = speed
  • d = distance
  • t = time

<u />

<u>Calculating the speed:</u>

<u />

1.) \frac{1.5-0}{20-0}=\frac{1.5}{20}=0.075

2.) \frac{1.5-1.5}{40-20}=\frac{0}{20}=0

3.) \frac{0-1.5}{50-40}=\frac{-1.5}{10}=-0.15

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A small ball with mass 1.20 kg is mounted on one end of a rod 0.860 m long and of negligible mass. The system rotates in a horiz
Rufina [12.5K]

Answer:

0.88752 kgm²

0.02236 Nm

Explanation:

m = Mass of ball = 1.2 kg

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\theta = Angle = 90°

Rotational inertia is given by

I=mL^2\\\Rightarrow I=1.2\times 0.86^2\\\Rightarrow I=0.88752\ kgm^2

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5 0
3 years ago
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dezoksy [38]

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3 0
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3 years ago
A 8.8 cm diameter circular loop of wire is in a 1.04 T magnetic field. The loop is removed from the field in 0.30 s . Assume tha
denis23 [38]

Answer:

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Explanation:

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<u>Where:</u>

<em>N = is the number of turns = 1   </em>

<em>ΔΦ = ΔB*A                                            </em>

<em>Δt = is the time = 0.3 s   </em>

<em>A = is the loop of wire area = πr² = πd²/4 </em>

<em>ΔB: is the magnetic field = (0 - 1.04) T                     </em>

Hence the average induced emf is:

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I hope it helps you!

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3 years ago
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Answer:

B

Explanation:

i had a test on this and got it correct

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