Answer:
Zn(s) → Zn⁺²(aq) + 2e⁻
Explanation:
Let us consider the complete redox reaction:
Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g)
This is a redox reaction because, both oxidation and reduction is simultaneously taking place.
- Oxidation (loss of electrons or increase in the oxidation state of entity)
- Reduction (gain of electrons or decrease in the oxidation state of the entity)
- An element undergoes oxidation or reduction in order to achieve a stable configuration. It can be an octet configuration. An octet configuration is that of outer shell configuration of noble gas.
Here Zn(s) is undergoing oxidation from OS 0 to +2
And H in HCl (aq) is undergoing reduction from OS +1 to 0.
Therefore, for this reaction;
Oxidation Half equation is:
Zn(s) → Zn⁺²(aq) + 2e⁻
Reduction Half equation is:
2H⁺ + 2e⁻ → H₂(g)
Photosynethesis, respiration, and combustion.
- Endothermic reaction means the reactant side takes heat from surrounding and get decomposed i.e ∆H=-ve
- If the equation is exothermic then it means the reactant is happy to decompose .But it's not as it's endothermic
Now
- HgO is Omitted from our solution option.
Hg is a atom so no bonds hence no bond strength occurs.
- O_2 is a molecule and so it's our answer .
10H₂ + 5O₂ → 10H₂O
Explanation:
This problem deals with balancing of chemical equations. In balancing chemical equations, the law of conservation of mass must be followed. This states that:
"In a chemical reaction, matter is neither created nor destroyed but transformed from one form to another".
This meaning of this is that; the number of atoms on each side of the expression must be the same.
2H₂ + O₂ → 2H₂O
let us check is the equation above is balanced;
2H₂ + O₂ → 2H₂O
Elements reactant product
H 4 4
O 2 2
We can see vividly that the equation is balanced;
Now; if we have 5 oxygen gas, we multiply the equation through by 5:
5 x ( 2H₂ + O₂ → 2H₂O )
⇒ 10H₂ + 5O₂ → 10H₂O
Elements reactant product
H 20 20
O 10 10
learn more:
Balanced equation brainly.com/question/11102790
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Answer:
B.Lone pair in pyrrolidine ring is localized and, therefore, is expected to be more reactive.
Explanation:
There are two nitrogen atoms bearing lone pairs of electrons in the structure of nicotine as shown in the image attached.
One nitrogen atom is found in the pyrrolidine ring. The lone pair on this nitrogen atom is localized hence it is more reactive than the lone pair of electrons found on the nitrogen atom in the pyridine ring which is delocalized a shown in the image attached to this answer.
