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bazaltina [42]
3 years ago
14

A force of 24 N acts on an 8 kg rock. What is the acceleration of the rock?

Chemistry
1 answer:
a_sh-v [17]3 years ago
3 0

Answer: 3m/s2

Explanation:

Force =24 N

Mass = 8kg

Acceleration =?

Force = Mass x Acceleration

Acceleration = Force /Mass = 24/8 = 3m/s2

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What did James Cameron use on his 2nd visit to this famous ship to look inside?
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7 0
2 years ago
A balloon filled with helium has a volume of 4.5 × 103 L at 25°C. What volume will the balloon occupy at 50°C if the pressure su
Tom [10]

Answer:

V_2 = 4.87 * 10^3

Explanation:

This question is an illustration of ideal Gas Law;

The given parameters are as follows;

Initial Temperature = 25C

Initial Volume = 4.5 * 10³L

Required

Calculate the volume when temperature is 50C

NB: Pressure remains constant;

Ideal Gas Law states that;

PV = nRT

The question states that the pressure is constant; this implies that the constant in the above formula are P, R and n

Divide both sides by PT

\frac{PV}{PT} = \frac{nRT}{PT}

\frac{V}{T} = \frac{nR}{P}

Represent \frac{nR}{P} with k

\frac{V}{T} = k

k = \frac{V_1}{T_1} = \frac{V_2}{T_2}

At this point, we can solve for the required parameter using the following;

\frac{V_1}{T_1} = \frac{V_2}{T_2}

Where V1 and V2 represent the initial & final volume and T1 and T2 represent the initial and final temperature;

From the given parameters;

V1 = 4.5 * 10³L

T1 = 25C

T2 = 50C

Convert temperatures to degree kelvin

V1 = 4.5 * 10³L

T1 = 25 +273 = 298K

T2 = 50 + 273 = 323K

Substitute values for V1, T1 and T2 in \frac{V_1}{T_1} = \frac{V_2}{T_2}

\frac{4.5 * 10^3}{298} = \frac{V_2}{323}

Multiply both sides by 323

323 * \frac{4.5 * 10^3}{298} = \frac{V_2}{323} * 323

323 * \frac{4.5 * 10^3}{298} = V_2

V_2 = 323 * \frac{4.5 * 10^3}{298}

V_2 = \frac{323 * 4.5 * 10^3}{298}

V_2 = \frac{1453.5 * 10^3}{298}

V_2 = 4.87 * 10^3

Hence, the final volume at 50C is V_2 = 4.87 * 10^3

7 0
3 years ago
Amines do not ionize in water.<br> True or False
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Answer:

This is a true statement

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