Two metal plates 4 cm long are held horizontally 3 cm apart in a vacuum, one being vertically above other. The upper plate is at
1 answer:
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Answer:
The value is
Explanation:
From the we are told that
The initial speed of the object is
The greatest height it reached is
Generally from kinematic equation we have that
At maximum height v = 0 m/s
So
=>
Here H is the height from the initial height to the maximum height
So the initial height is mathematically represented as
=>
=>
Generally the time taken for the object to reach maximum height is mathematically evaluated using kinematic equation as follows
At maximum height v = 0 m/s
=>
Generally the time taken for the object to move from the maximum height to the ground is mathematically using kinematic equation as follows
Here the initial velocity is 0 m/s given that its the velocity at maximum height
Also g is positive because we are moving in the direction of gravity
So
=>
Generally the total time taken is mathematically represented as
=>
=>
Answer:
Part A:
Part B:
Option B (Towards the South)
Explanation:
Part A:
Magnitude if electric field E:
E=Force/charge
Force=2.04×10−14 N
Charge=1.6×10−19 C
Part B:
Option B (Towards the South)
As electron is experiencing the force towards south,it means the direction of the electric field is towards the south because direction of field lines is from positive to negative, so proton is moving towards south it means negative charge is in south to which proton is attracted. So electric field is towards South.
Answer:
2(maximum), -2(minimum), -2(maximum).
Explanation:
V(t)= 2πcos πt--------------------------------------------------------------------------------(1).
Therefore, there is a need to integrate v(t) to get S(t).
S(t)= 2×sinπt + C ------------------------------------------------------------------------------(2).
Applying the condition given, we have s(0)= 0.
S(0)= 2sin ×π(0) + C.
Which means that; 0+C= 0. That is; C=0.
S(t)= 2 sin πt.
The mass moves to its highest positions at time,t=half(1/2=.5) and time,t=2.5.
Take note that; sin(π/2) = sin(5π/2) = 1 .
Also, the mass moves to its lowest position at time,t=(3/2); also, sin(3π/2) = -1.
Therefore, we have that 2 maximum; -2 minimum and -2 maximum.
