1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lelechka [254]
2 years ago
10

On top of a 3 m tall shelf sits a lonely 4.5 kg toy snake. How much GPE does this snake have if the shelf is on Earth? (g = 9.8

m/s?
answer =
Physics
1 answer:
Readme [11.4K]2 years ago
8 0

Answer:

GPE = Mgh = 132J

Explanation:

Mgh

4.5×9.8×3

132J

You might be interested in
A sphere moves in simple harmonic motion with a frequency of 4.80 Hz and an amplitude of 3.40 cm. (a) Through what total distanc
geniusboy [140]

Answer:

a)  the total distance traveled by the sphere during one cycle of its motion = 13.60 cm

b) The maximum speed is = 102.54 cm/s

The maximum speed occurs at maximum excursion from equilibrium.

c)  The maximum magnitude of the acceleration of the sphere is = 30.93 m/s^2

The maximum acceleration occurs at maximum excursion from equilibrium.

Explanation:

Given that :

Frequency (f) = 4.80 Hz

Amplitude (A) = 3.40 cm

a)

The total distance traveled by the sphere during one cycle of simple harmonic motion is:

d = 4A   (where A is the Amplitude)

d = 4(3.40 cm)

d = 13.60 cm

Hence, the total distance traveled by the sphere during one cycle of its motion = 13.60 cm

b)

As we all know that:

x = Asin \omega t

Differentiating the above expression with respect to x ; we have :

\frac{d}{dt}(x) = \frac{d}{dt}(Asin \omega t)

v = A \omega cos \omega t

Assuming the maximum value of the speed(v) takes place when cosine function is maximum and the maximum value for cosine function is 1 ;

Then:

v_{max} = A \omega

We can then say that the maximum speed therefore occurs at the mean (excursion) position where ; x = 0  i.e at maximum excursion from equilibrium

substituting 2 \pi f for \omega in the above expression;

v_{max} = A(2 \pi f)

v_{max} = 3.40 cm (2 \pi *4.80)

v_{max} = 102.54 \ cm/s

Therefore, the maximum speed is = 102.54 cm/s

The maximum speed occurs at maximum excursion from equilibrium.

c) Again;

v = A \omega cos \omega t

By differentiation with respect to  t;

\frac{d}{dt}(v) = \frac{d}{dt}(A \omega cos \omega t)

a =- A \omega^2 sin \omega t

The maximum acceleration of the sphere is;

a_{max} =A \omega^2

where;

w = 2 \pi f

a_{max} = A(2 \pi f)^2

where A= 3.40 cm = 0.034 m

a_{max} = 0.034*(2 \pi *4.80)^2

a_{max} = 30.93 \ m/s^2

The maximum magnitude of the acceleration of the sphere is = 30.93 m/s^2

The maximum acceleration occurs at maximum excursion from equilibrium where the oscillating sphere will have maximum acceleration at the turning points when the sphere has maximum displacement of x  = \pm A

6 0
3 years ago
‼️HELP HELP HELP‼️
Reil [10]

Answer:

sr Idontknow this

Explanation:

5 0
1 year ago
Explain how motion and energy are related to roller coasters, please be specific!
Fittoniya [83]
Because when an object is in motion it has kinetic energy
4 0
2 years ago
What would be the magnitude of the electric field 0.75 m from a 0.63 C master charge and what would be the force on a 0.50 C tes
bagirrra123 [75]

The magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.

<h3>Electric field on the master charge</h3>

E = kq/r²

where;

  • q is magnitude of master charge
  • r is distance of separation
  • k is Coulomb's constant

E = (9 x 10⁹ x 0.63)/(0.75²)

E = 1.008 x 10¹⁰ N/C

<h3>Force on the test charge</h3>

F = Eq

where;

  • E is electric field
  • q is the test charge

F = (1.008 x 10¹⁰) x (0.5)

F = 5.04 x 10⁹ N

Thus, the magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.

Learn more about electric field here: brainly.com/question/14372859

#SPJ1

8 0
1 year ago
Which of the following is not a use for a weather radar?
Elodia [21]
Weather radar is used to locate precipitation<span>, calculate its motion, and estimate its type rain, snow, </span>hail etc

so, d.measuring temperature <span>is not a use for a weather radar

</span>effect of global warming-<span>heavier rainfall and flooding</span>
5 0
3 years ago
Read 2 more answers
Other questions:
  • Consider a beam of electrons in a vacuum, passing through a very narrow slit of width 2.00μm. The electrons then head toward an
    9·1 answer
  • how did the environment in north america affect the development of american indian culture in period just before europeans arriv
    12·2 answers
  • Serena is a research student who has conducted an experiment on the discoloration of marble. Read about Serena’s experiment. The
    9·1 answer
  • How do scientist know that seismic waves can be either compressional or transverse
    12·1 answer
  • The table shows the potential energy and kinetic energy of a skier at two different positions on a hill.
    6·2 answers
  • What does a refractive index from medium 1 to medium 2 mean? Isn't one of the medium must be vacuum?
    6·1 answer
  • What items resemble the path of light when it travels through space?
    9·1 answer
  • 5. The entrance of a science museum features a funnel into which marbles are rolled one at a time. The marbles circle around the
    12·1 answer
  • 47. Calculate the final steady temperature obtained when
    7·1 answer
  • Work, Power, and Energy
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!