Question

Carbon monoxide (co) reacts with hydrogen (h2) to form methane (ch4) and water (h2o).co(

Answer 1

Answer is (b) - 5.9 x 10⁻².

Explanation;

The balanced reaction is

CO(g) + 3H₂(g) ⇄ CH₄(g) + H₂O(g)

We can write the equation for the equilibrium constant, Kc as follows,

Kc = ( [CH₄(g)] x [H₂O(g)] ) / ( [CO(g)] x [H₂(g)]³ )

Given data,

Kc = 3.90

[CO(g)] = 0.3 M

[H₂(g)] = 0.1 M

[CH₄(g)] = ?

[H₂O(g)] = 0.020 M

From substitution,

    3.90 = ( [CH₄(g)] x 0.020 ) / ( (0.10)³ x 0.30 )

[CH₄(g)] = ( 3.90 x 0.30 x (0.1)³ ) / 0.020

[CH₄(g)] = 0.0585

             = 0.059 = 5.9 x 10⁻²

Answer 2

The correct answer for this question is this one: d. 5.9 x 10^2
The reaction is at equilibrium at 1,000 k. the equilibrium constant of the reaction is 3.90. at equilibrium, the concentrations are as follows.[co] = 0.30 m[h2] = 0.10 m[h2o] = 0.020 m

The equilibrium concentration of ch4 expressed in scientific notation is
a. 0059
b. 5.9 x 10^-2
c. 0.059
d. 5.9 x 10^2

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