Cotton Balls are soft and pine cones are hard.
Molecular formula of Isoflurane is <span><span>C</span></span>₃H₂ClF₅O.
Now calculate
the percent composition by mass, which means percent of each element in the
compound.
Mass of Isoflurane
= 184.49 g/mol
Mass of carbon in the compound = 3 x
12.011 = 36.033g
Mass of hydrogen in the compound = 2 x
1.008 = 2.016g
Mass of chlorine in the compound = 1 x 35.453
= 35.453 g
Mass of fluorine in the compound = 5 x 18.998
= 94.99g
Mass of Oxygen in the compound = 1 x 16
= 16 g
Carbon’s percentage = Mass of carbon in
the compound /mass of isoflurane x 100 =36.033/184.49 x 100 =19.53%
Hydrogen’s Percentage = Mass of hydrogen
in the compound/mass of isoflurane x 100 = 2.016/184.49 = 1.09%
Chlorine’s percentage = Mass of chlorine
in the compound/mass of isoflurane x 100 = 35.453/184.49 =19.22%
Flourine’s percentage = Mass of fluorine
in the compound/mass of isoflurane x 100 = 94.99/184.49 x 100 = 51.49%
Oxygen’s percentage = Mass of Oxygen in
the compound/mass of isoflurane x 100 =16/184.49 x 100 = 8.67%
<span> </span>
Answer:
The Etna volcano when it previously erupted released a lot of smoke, and then volcanic lava.
Explanation:
The eruption of this volcano was on the Italian island of Sicily.
Where there were large columns of smoke and after that the volcanic magma in a viscoelastic state was released into the external environment.
Some sources claim that the eruption of this volcano reached the areas of Zaffanera.
The question mentions a change in temperature from 25 to 50 °C. With that, the aim of the question is to determine the change in volume based on that change in temperature. Therefore this question is based on Gay- Lussac's Gas Law which notes that an increase in temperature, causes an increase in pressure since the two are directly proportional (once volume remains constant). Thus Gay-Lussac's Equation can be used to solve for the answer.
Boyle's Equation:

=

Since the initial temperature (T₁) is 25 C, the final temperature is 50 C (T₂) and the initial pressure (P₁) is 103 kPa, then we can substitute these into the equation to find the final pressure (P₂).

=

∴ by substituting the known values, ⇒ (103 kPa) ÷ (25 °C) = (P₂) ÷ (50 °C)
⇒ P₂ = (4.12 kPa · °C) (50 °C)
=
206 kPa
Thus the pressure of the gas since the temperature was raised from 25 °C to 50 °C is
206 kPa