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3 years ago

What is the weight in grams of 3.36 × 1023 molecules of copper sulfate (CuSO4)?

Chemistry

2 answers:

Mekhanik [1.2K]3 years ago

8 0

<u>Answer:</u> The mass of given amount of molecules of copper sulfate is 89.054 grams.

<u>Explanation:</u>

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules.

The mass of 1 mole of copper sulfate = 159.609 grams

As, $6.022\times 10^[23}$ number of molecules have a mass of 159.609 grams.

So, $3.36\times 10^{23}$ number of molecules will have a mass of $\frac{159.609g}{6.022\times 10^{23}}\times 3.36\times 10^{23}=89.054g$

Thus, the mass of given amount of molecules of copper sulfate is 89.054 grams.

Juli2301 [7.4K]3 years ago

7 0

Molar mass of cuso4=63.5+32+4*16= 159.5 g
6.02*10^23 molecules weigh=159.5 g
1 molecule weigh=159.5/6.02*10^23 g
3.36 × 10^23 molecules weigh=159.5/6.02*10^23*3.36× 10^23
=89.023g

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2 years ago

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gogolik [260]

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3 years ago

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Answer:

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2 years ago