Complete question:
A spirit burner used 1.00 g methanol to raise the temperature of 100.0 g water in a metal can from 28.00C to 58.0C. Calculate the heat of combustion of methanol in kJ/mol.
Answer:
the heat of combustion of the methanol is 402.31 kJ/mol
Explanation:
Given;
mass of water, 
= 100 g
initial temperature of water, t₁ = 28 ⁰C
final temperature of water, t₂ = 58 ⁰C
specific heat capacity of water = 4.184 J/g⁰C
reacting mass of the methanol, m = 1.00 g
molecular mass of methanol = 32.04 g/mol
number of moles = 1 / 32.04
= 0.0312 mol
Apply the principle of conservation of energy;
Therefore, the heat of combustion of the methanol is 402.31 kJ/mol
Answer:
The hot water remains at the top of chilled water.
Explanation:
The hot water remains at the top of chilled water because hot water has less denser as compared to chilled water. Due to higher density of chilled water, it remains at the bottom due to its greater mass while on the other hand, the hot freshwater goes upward and spreads at the top of the chilled water due to lower mass so when the hot water is added to the chilled water, hot water remains at the top.
Answer:
if insects helps in pollination that is called entomophily
Explanation:
Some plants having attractive odor and color which attracted the insects towards it and when they come in contact with flowering plant the seed or pollens which is produced by the male part of plant got attached to their body and when insects travels to other flowering plants pollens sheds to stigma which is female part of flower and in results fertilization occur.
Answer:
How is the ocean important to human survival? The air we breathe: The ocean produces over half of the world's oxygen and absorbs 50 times more carbon dioxide than our atmosphere. Climate regulation: Covering 70 percent of the Earth's surface, the ocean transports heat from the equator to the poles, regulating our climate and weather patterns
Explanation:
Answer: 14.62 ml
Explanation:
Molarity is defined as the number of moles of solute dissolved per liter of the solution.
where,
n= moles of solute
= volume of solution in ml = 250 ml
Now put all the given values in the formula of molarity, we get
To calculate the volume of base, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
Thus the volume of NaOH solution the student will need to add to reach the final equivalence point is 14.62 ml
