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sveta [45]
3 years ago
15

Displaement of ammonia from its salt

Chemistry
1 answer:
Dvinal [7]3 years ago
5 0
Ill say <span>calcium hydroxide but hope this helps :)</span>
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Define electronegativity<br>​
stira [4]

Answer: Electronegativity is a measure of the tendency of an atom to attract a bonding pair of electrons.

Explanation: Hope this helps!

6 0
3 years ago
determine the grams of NH3 produced when 6.70 grams of N2 is consumed using the following equation: N2 + 3H2 = 2NH3 ​
tangare [24]

Answer:

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8 0
3 years ago
If 50. 75 g of a gas occupies 10. 0 l at stp, 129. 3 g of the gas will occupy ________ l at stp.
NeX [460]

22.4L

of any gas contains 1 mol of that gas.

50.75g/10L*22.4L/1 mol= 113.68g/mol- this is the mole weight of your gas

1 mol/113.68g*129.3g=1.137403 mol

Set up a ratio

1.137403mol/x L=1 mol/22.4 L

X=25.477827L, or with sig figs, x=25.5L

8 0
2 years ago
Collected data consists of:
san4es73 [151]

The number of moles of the magnesium (mg) is 0.00067 mol.

The number of moles of hydrogen gas is 0.0008 mol.

The volume of 1 more hydrogen gas (mL) at STP is 22.4 L.

<h3>Number of moles of the magnesium (mg)</h3>

The number of moles of the magnesium (mg) is calculated as follows;

number of moles = reacting mass / molar mass

molar mass of magnesium (mg) = 24 g/mol

number of moles = 0.016 g / 24 g/mol = 0.00067 mol.

<h3>Number of moles of hydrogen gas</h3>

PV = nRT

n = PV/RT

Apply Boyle's law to determine the change in volume.

P1V1 = P2V2

V2 = (P1V1)/P2

V2 = (101.39 x 146)/(116.54)

V2 = 127.02 mL

Now determine the number of moles using the following value of ideal constant.

R = 8.314 LkPa/mol.K

n = (15.15 kPa x 0.127 L)/(8.314 x 290.95)

n = 0.0008

<h3>Volume of 1 mole of hydrogen gas at STP</h3>

V = nRT/P

V = (1 x 8.314 x 273) / (101.325)

V = 22.4 L

Learn more about number of moles here: brainly.com/question/13314627

#SPJ1

7 0
1 year ago
Is facilitated diffusion passive or active transport?
bazaltina [42]

Answer:

Its passive

Explanation:

Facilitated diffusion is a type of passive transport that allows substances to cross membranes with the assistance of special transport proteins.

6 0
3 years ago
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