Answer:
nCl= 0,062x3/2=0,093(mol)
Explanation:
Answer:
41264 g of CO₂
Explanation:
Combustion reaction is:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
1 mol of propane react to 5 moles of oxygen in order to proudce 3 moles of carbon dioxide and 4 moles of water.
In a combustion reaction, our reactant reacts to oxygen and the products are always CO₂ and water.
We have the volume of propane but we need moles of it, so we need to apply density.
Density = mass / volume so mass = density . volume.
Density of propane is: 493 g/L
Mass of propane is 493 g/L . 27.9L = 13754.7 g
We convert mass to moles: 13754.7 g . 1 mol/ 44g = 312.6 moles
According to reaction, 1 mol of propane can produce 3 moles of CO₂
Our 312.6 moles will produce 312.6 . 3 = 937.8 moles
We convert moles to mass: 937.8 mol . 44 g/mol = 41264 g
The pH of the diluted HCl solution is 1.3.
Explanation:
Given:
The concentrated HCl solution of 8.0 M. The 1.5 mL of 8.0 M HCl is diluted with water to 250 mL volume.
To find:
The pH of the diluted HCl solution.
Solution
- The concentration of the HCl solution before dilution =
- The volume of the HCl solution taken for dilution =
- The concentration of the HCl solution after dilution =
- The volume of the HCl solution after dilution =
Using the Dilution equation:
The concentration of diluted HCl solution = 0.048 M
In the 1 M solution of HCl, there are 1 M of hydrogen ion, then the concentration of hydrogen ions in 0.048 M of HCl will be:
![[H^+]=1\times 0.048M=0.048 M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D1%5Ctimes%200.048M%3D0.048%20M)
The pH of the diluted HCl solution :
![pH=-\log [H^+]\\=-\log [0.048M]=1.18 \approx 1.3](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D%5C%5C%3D-%5Clog%20%5B0.048M%5D%3D1.18%20%5Capprox%201.3)
The pH of the diluted HCl solution is 1.3.
Learn more about the dilution equation here:
brainly.com/question/24546169?referrer=searchResults
brainly.com/question/1199928?referrer=searchResults
Answer:
<em>The mole ratio of PbO2 to H2O is 1 : 2.</em>
Explanation:
The balanced reaction equation is:
Pb + PbO2 + 2H2SO4 → 2PbSO4 + 2H2O
On the reactant side, we have 1 mole of Pb, 1 mole of PbO2, 2 moles of H2SO4.
On the product side, we have 2 moles of PbSO4 and 2 moles of H2O.
This means that for ever 1 mole of PbO2 consumed, 2 moles of water is formed as product.
Hence, the mole ratio of PbO2 to H2O is 1 : 2.
Answer:
no
Explanation:
if you are referring to the first question, the answer is no. the equation is unbalanced because the left side has 4 hydrogens and the right has only 2, and the left has 2 oxygens while the right has 3. this means it does not follow the law of conservation of mass because each side has a different mass.
