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3 years ago

Please help me with chemistry!

Chemistry

1 answer:

Helga [31]3 years ago

5 0

Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)

Explanation:

Reacting bromide (Br₂) with sodium iodine (NaI) will produce sodium bromide (NaBr) and iodine (I₂).

To balance the equation the number of atoms of each element entering the reaction have to be equal to the number of atoms of each element leaving the reaction, in order to conserve the mass.

Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)

where:

l - liquid

s - solid

This is a single replacement reaction because an element in a compound is replaced by another element. Generally a single replacement reaction is represented as: A + BC → AC + B

Learn more about:

types of chemical reactions

brainly.com/question/10105284

balancing chemical equations

brainly.com/question/13908054

#learnwithBrainly

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Peroxyacylnitrate (PAN) is one of the components

coldgirl [10]

C – 19,9%, H – 2,2%, N – 11,6%, O – x%

$M=120\frac{g}{mol}$

1 percentage

The entire molecule is 100% and all the components of the compound add up to 100%.

100% - 19,9% - 2,5% - 11,6% = 66,1%

The compound contains 66,1% oxygen.

2 molar masses

$M_{C}=12,01\frac{g}{mol}$

$M_{H}=1,008\frac{g}{mol}$

$M_{O}=15,999\frac{g}{mol}$

$M_{N}=14,007\frac{g}{mol}$

3 masses

The compound has a molar mass of 120g/mol. So one molecule weighs 120 g. To find out how much the percentage of a component weighs, you have to calculate it using the molar mass.

carbon

19,8% of 120g

$m=120g*0,198\\m=23,76g$

One molecule contains 23,76g of carbon.

hydrogen

2,5% of 120g

$m=120g*0,025\\m=3g$

One molecule contains 3g of hydrogen.

oxygen

66,1% of 120g

$m=120g*0,661\\m=79,32g$

One molecule contains 79,32g of oxygen.

nitrogen

11,6% of 120g

$m=120g*0,0,116\\m=13,92g$

One molecule contains 13,92g of nitrogen.

4 amount of substance

carbon

$n=\frac{23,76g}{12,01\frac{g}{mol} }\\n=1,98mol$

The compound contains about 2 moles of carbon.

hydrogen

$n=\frac{3g}{1\frac{g}{mol} }\\n=3mol$

The compound contains about 3 moles of hydrogen.

oxygen

$n=\frac{79,32g}{15,999\frac{g}{mol} }\\n=4,96mol$

The compound contains about 5 moles of oxygen.

nitrogen

$n=\frac{13,92g}{14,007\frac{g}{mol} }\\n=0,99mol$

The compound contains about 1 moles of nitrogen.

5. molecular formula

The formula results from the ratio of the amounts of substance.

$n_{C} :n_{H} :n_{O} :n_{N} =2:3:5:1\\C_{2}H_{3}NO_{5}$

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