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Nimfa-mama [501]
3 years ago
3

In an effusion experiment it required 40 s for a certain number of moles of a gas of unknown molar mass to pass through a small

orifice into a vacuum. Under the same conditions 16 s were required for the same number of moles of O2 to effuse. What is the molar mass of the unknown gas?
Chemistry
1 answer:
Aleksandr-060686 [28]3 years ago
7 0

The molar  mass  of the unknown   gas  is  200  g/mol


<u><em>calculation</em></u>

let  the  unknown  gas  be represented   by  Y and molar mass be represented by  MM

The  molar mass of Y  is  therefore calculated  using  

 = (time of Y/ time of O2) =√(MM  of Y/ MM of O2 formula.

where  MM of  y =?

        MM of   O2 = 32  g/mol

       time  of Y = 40 s

      time   of O2 = 16  s

40/16 =√ (MM  of Y/ 32)

2.5=√MM   of Y/32

square  both side to remove the √ sign

6.25 =MM  of Y/32

multiply both side  by 32

MM of Y  is therefore= 200 g /mol


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Calculate the specific heat capacity of a piece of ice if 1.30 kg of the wood absorbs 6.75×104 joules of heat, and its temperatu
Gre4nikov [31]

Answer:

c=2.0769\  \frac{J}{g\ \textdegree C}

Explanation:

-Specific heat capacity is given by the formula:

q=mc\bigtriangleup T

Where:

q is the heat gained or loosed by the substance

m is the mass of the substance

c is the specific heat of the substance

\bigtriangleup T is the change in temperature

#We make c the subject of the formula and substitute to solve for it:

q=mc\bigtriangleup T\\\\c=\frac{q}{m\bigtriangleup T}\\\\\bigtriangleup T=(57-32)\textdegree C=25\textdegree C\\\\\therefore c=\frac{6.75\times 10^4J}{1.3\times 1000\ g\times 25\textdegree  C}\\\\=2.0769 \ \frac{J}{g\ \textdegree C}

Hence, the specific heat capacity of the ice is 2.0769 \frac{J}{g\ \textdegree C}

8 0
4 years ago
The acid-dissociation constant of hydrocyanic acid (hcn) at 25.0 °c is 4.9 ⋅ 10−10. what is the ph of an aqueous solution of 0.0
vodomira [7]
According to the reaction equation:

and by using ICE table:

              CN-  + H2O ↔ HCN  + OH- 

initial  0.08                        0          0

change -X                        +X          +X

Equ    (0.08-X)                    X            X

so from the equilibrium equation, we can get Ka expression

when Ka = [HCN] [OH-]/[CN-]

when Ka = Kw/Kb

               = (1 x 10^-14) / (4.9 x 10^-10)

               = 2 x 10^-5

So, by substitution:

2 x 10^-5 = X^2 / (0.08 - X)

X= 0.0013

∴ [OH] = X = 0.0013 

∴ POH = -㏒[OH]

            = -㏒0.0013

            = 2.886 

∴ PH = 14 - POH

         = 14 - 2.886 = 11.11
5 0
3 years ago
Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch
mamaluj [8]

Answer:

Explanation:

From the given information:

The equation for the reaction can be represented as:

2SO_2 + O_2 \to 2SO_3

The I.C.E table can be represented as:

                     2SO₂              O₂                   2SO₃

Initial:             14                  2.6                     0

Change:        -2x                -x                      +2x

Equilibrium:   14 - 2x          2.6 - x                2x

However, Since the amount of sulfur trioxide gas to be 1.6 mol.

SO₃ = 2x,

then x = 1.6/2

x = 0.8 mol

For 2SO₂; we have 14 - 2x

= 14 - 2(0.8)

= 14 - 1.6

= 12.4 mol

For O₂; we have 2.6 - x

= 2.6 - 1.6

= 1.0 mol

Thus;

[SO₂] = moles / volume = ( 12.4/50) = 0.248 M ,

[O₂] = 1/50 = 0.02 M ,  

[SO₃] = 1.6/50 = 0.032 M

Kc = [SO₃]² / [SO₂]² [O₂]

= ( 0.032²) / ( 0.248² x 0.02)

= 0.8325

Recall that; the equilibrium constant for the reaction 2SO_2 + O_2 \to 2SO_3 = 0.8325;

If we want to find:

SO_2 + \dfrac{1}{2}O_2 \to SO_3

Then:

K_c = (0.8325)^{1/2}

\mathbf{K_c = 0.912}

Since no temperature is given to use in the question, it will be impossible to find the final temperature of the mixture.

7 0
3 years ago
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Anvisha [2.4K]

Answer:

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8 0
3 years ago
IBNEED HELP ASAP<br> NO BULL I NEED ACTUAL HELP
Alja [10]

Answer:

god says dont use any assault language okay?

Explanation:

5 0
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