The additional volume of HCl which must be added to reach to the equivalence point is 8.33 mL
The moles of HCl which is required to reach the equivalence point can be calculated in the way as follows.
Moles of HCl can be calculated as
Moles of HCl = 0.004 moles of Ca (OH) 2 × 2 moles of HCl / 1 moles of Ca (OH) 2
= 0.008 moles of HCl
The volume of HCl which is required to reach the equivalence point can be calculated in the way given as follows.
Volume of HCl required= 0.008 moles of HCl × 1 L / 0.24 moles of HCl × 1 ml / 10 -³ L
= 33.33 ml
The additional volume of HCl calculated as
Additional volume = required volume – actual volume
= 33.33 mL – 25 mL
= 8 . 33 mL
Thus, we calculated that the additional volume of HCl which must be added to reach to the equivalence point is 8.33 mL.
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Answer:
The increasing order of masses of molecule ions:
118 g/mol(75.8%) , 120 g/mol(24.2%)
Explanation:
Chlorine occurs as 35-Cl (75.8%) and 37-Cl (24.2%).
Atomic mass of 35-Cl = 35 g/mol
Atomic mass of 37-Cl = 37 g/mol
Mass of Chlorocyclohexane in which 35-cl is present as a chlorine atom: ![C_6H_{11}Cl](https://tex.z-dn.net/?f=C_6H_%7B11%7DCl)
![=6\times 12 g/mol+11\times 1 g/mol+1\times 35 g/mol=118 g/mol](https://tex.z-dn.net/?f=%3D6%5Ctimes%2012%20g%2Fmol%2B11%5Ctimes%201%20g%2Fmol%2B1%5Ctimes%2035%20g%2Fmol%3D118%20g%2Fmol)
Mass of Chlorocyclohexane in which 37-Cl is present as a chlorine atom: ![C_6H_{11}Cl](https://tex.z-dn.net/?f=C_6H_%7B11%7DCl)
![=6\times 12 g/mol+11\times 1 g/mol+1\times 37 g/mol=120 g/mol](https://tex.z-dn.net/?f=%3D6%5Ctimes%2012%20g%2Fmol%2B11%5Ctimes%201%20g%2Fmol%2B1%5Ctimes%2037%20g%2Fmol%3D120%20g%2Fmol)
The increasing order of masses of molecule ions:
118 g/mol(75.8%) < 120 g/mol(24.2%)
Answer:
Explanation:
Answer is B i got it right
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