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Marizza181 [45]
3 years ago
13

IBNEED HELP ASAP NO BULL I NEED ACTUAL HELP

Chemistry
1 answer:
Alja [10]3 years ago
5 0

Answer:

god says dont use any assault language okay?

Explanation:

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Calculate the ph of a solution with a [H3O+]=5.6x10-9M
Kisachek [45]

Answer:

               pH  =  8.25

Explanation:

                   The acidity or basicity of a solution is measured by its pH. The pH scale ranges from 0 to 14. Solutions having pH from 0-6.9 are considered acidic, at 7 neutral and basic when ranging from 7.1-14.

pH is calculated as,

                                 pH  =  - log [H⁺]   ---- (1)

Where;

            [H⁺]  =  concentration of Acid

Also, for bases pH i calculated using following formula,

                                 pH  =  14 - pOH

Therefore, Putting value of H⁺ in equation 1,

                                 pH  =  - log [5.6 × 10⁻⁹]

                                pH =  8.25

The solution provided is basic in nature.

6 0
3 years ago
How many moles of magnesium, Mg, are there in 4.75 grams of magnesium?
Nina [5.8K]
Molar mass Mg = 24.3 g/mol

1 mole mg ------------ 24.3 g
?? moles mg --------- 4.75 g

4.75 x 1 / 24.3 => 0.195 moles of Mg

hope this helps!
3 0
3 years ago
If 15.0 mL of phosphoric acid completely neutralizes 38.5 mL of 0.150 mol/L calcium hydroxide, what is the concentration of the
Sedbober [7]

Answer:

Let me give it a try.

H3PO4 + Ca(OH)2 = Ca3(PO4)2 + H2O

Balancing this reaction

2H3PO4 + 3Ca(OH)2 == Ca3(PO4)2 + 6H2O.

Moles= Molarity x Volume

Volume = 38.5ml = 0.0385L

Moles of Ca hydroxide = 0.150m/L x 0.0385L

(Notice the units canceling out...leaving moles).

=0.005775moles of Ca(OH)2.

From balanced reaction...

3moles of Ca(OH)2 completely reacts with 2moles of H3PO4

0.005775moles of Ca(OH)2 would completely react with....

= 0.005775 x 2/(3)

=0.00385moles of H3PO4.

Now we're looking for its Concentration in Mol/L

Molarity=Moles of solute/Volume of solution(in L)

Volume of solution assuming no other additions to the reaction = 15ml + 38.5ml =53.5ml =0.0535L

Molarity = 0.00385/0.0535

=0.072Mol/L.

If this is wrong

then Simply Try The formula for Mixing of solutions

C1V1 = C2V2

0.15 x 38.5 = C2 x (15+38.5)

C2 = 0.11M/L.

7 0
3 years ago
If 56.8 ml of bacl2 solution is needed to precipitate all the sulfate ion in a 554 mg sample of na2so4 (forming baso4), what is
IrinaVladis [17]
<span>0.0687 m The balanced equation is BaCl2 + Na2SO4 ==> BaSO4 + 2 NaCl Looking at the equation, it indicates that there's a 1 to 1 ratio of BaCl2 and Na2SO4 in the reaction. So the number of moles of each will be equal. Now calculate the number of moles of Na2SO4 we had. Start by looking up atomic weights. Atomic weight sodium = 22.989769 Atomic weight sulfur = 32.065 Atomic weight oxygen = 15.999 Molar mass Na2SO4 = 2 * 22.989769 + 32.065 + 4 * 15.999 = 142.040538 g/mol Moles Na2SO4 = 0.554 g / 142.040538 g/mol = 0.003900295 mol Molarity is defined as moles per liter, so let's do the division. 0.003900295 mol / 0.0568 l = 0.068667165 mol/l = 0.068667165 m Rounding to 3 significant figures gives 0.0687 m</span>
3 0
3 years ago
ICI(g) + Cl₂(g) → ICl3(s). The AG(f) of ICI(g) is -5.5 kJ/mol and the
DENIUS [597]

Answer:

KJ8RT898TGHO7-6734354546746R476

Explanation:

3 0
2 years ago
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