Answer:
v₂' = 19 m/s
Explanation:
given,
mass of car one = m₁ = 2000 Kg
mass of car two = m₂ = 1000 Kg
velocity of car one in right (v₁) = 10 m/s
velocity of car two in left (v₂)= 15 m/s
after collision
velocity(v₁') = 7 m/s
v₂' = ?
using conservation of momentum
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
2000 x 10 - 1000 x 15 = - 2000 x 7 + 1000 v₂'
1000 v₂' = 19000
v₂' = 19 m/s
The current is defined as the quantity of charge Q that passes through a certain location in a time

:

Using the data of the problem, we find:
Answer:
The ones that are after the light that went out are also out.
Explanation:
Answer:
0.43 s
Explanation:
We have the following parameters:
Initial velocity, u = 7.4 m/s
Acceleration of gravity, g = 9.8 
Distance, s = 43 in + 10 ft = 1.092 m + 3.048 m = 4.14 m
Time, t = ?
Using the equation of motion
, we have


Using the quadratic formula
where a = 4.9, b = 7.4 and c = - 4.14, and solving for the positive value of t only, we have
s