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3 years ago

Name six processes that are often involved in scientific inquiry.

1 answer:

6 0

1. Name 6 processes that are often involved in scientific inquiry.
Scientific inquiry refers to an activity of a certain person in where he or she needs to study a certain thing to be able to get knowledge and understand the scientific ideas of it on how scientists study it.
Here are the 6 process that are usually involved:
=> asking questions
=> Doing research
=> Make a Hypothesis
=> Testing the hypothesis through experiments
=> analyzing the data and draw a conclusion
=> show your result.

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Two solenoids of equal length are each made of 2000 turns of copper wire per meter. Solenoid I has a 5.00 cm radius; solenoid II

Nookie1986 [14]

Answer:

BI/BII = 1

Explanation:

The magnetic field due to a solenoid is given by the following formula:

$B = \mu nI\\$

where,

B = Magnetic Field due to solenoid

μ = permeability of free space

n = No. of turns per unit length

I = current passing through the solenoid

Now for the first solenoid:

$B_1 = \mu n_1I_1 \\$

For the second solenoid:

$B_2 = \mu n_2I_2\\$

Dividing both equations:

$\frac{B_1}{B_2} = \frac{\mu n_1I_1}{\mu n_2I_2}\\$

here, no. of turns and the current passing through each solenoid is same:

n₁ = n₂ and I₁ = I₂

Therefore,

$\frac{B_1}{B_2} = \frac{\mu nI}{\mu nI}\\$

BI/BII = 1

5 0

2 years ago

A 4.6-kg block of ice originally at 263 K is placed in thermal contact with a 15.7-kg block of silver (cAg = 233 J/kg-K) which i

Viktor [21]

Answer:

temperature at 326.44 K system achieve equilibrium

Explanation:

given data

mass of block of ice = 4.6 kg

temperature = 263 K

thermal contact = 15.7-kg

specific heat of silver cAg = 233 J/kg-K

initially temperature = 1052 K

to find out

what temperature will the system achieve equilibrium

solution

first we consider final temperature of the system is T

we know that specific heat of water (C w) = 4186 J(kg K)

and

specific heat of ice ( C i ) = 2030 J/(kg K)

and

latent heat of fusion of ice ( Lf ) = 3.33 × $10^{5}$ J/kg

and we know that system is insulated

so heat lost by silver = heat generated by ice .................1

so we can say

mass of silver × specific heat of silver × ( initial temp - final temp ) = mass of ice × specific heat of ice × ( ice temp ) + mass of ice × latent heat of fusion of ice + mass of ice × specific heat of water × (final temperature )

put here value we get

15.7 × 233 × ( 1052 - T ) = 4.6 × 2030 × 10 + 4.6 × 3.33 × $10^{5}$ + 4.6 × 4286 × ( T - 273 )

solve we get

T = 326.44 K

so temperature at 326.44 K system achieve equilibrium

7 0

3 years ago

If the child pulls with a force of 20 N for 12.0 m , and the handle of the wagon is inclined at an angle of 25 ∘ above the horiz

lilavasa [31]

Answer: 217.52 N

Explanation: The applied force is 20 N, the distance covered is 12.0 m and the angle is 25° above the horizontal.

Hence the formulae that defines work done is given by

W = Force × distance

But since the force has been inclined at an angle θ above the horizontal, the horizontal component of force is neccesary to produce the required motion to make the child do work on the wagon.

Hence

Work done = (horizontal component of force) × distance

Work done = F cos θ × distance

Work done = 20 cos 25 × 12 = 217.52 N

4 0

3 years ago

5. One of the attractions at Typhoon Lagoon, a water park in Florida, is a surf

tino4ka555 [31]

Answer:

1595790 gallons

Explanation:

Given that;

3.8 L = 1 US gallon

303,200.0 liters = 303,200.0 * 1/ 3.8 = 79789.5 gallons

If a wave is made every 90 seconds which is 1.5 mins

Then;

Number of waves made in 30 minutes = 30/1.5 = 20 waves

if each uses 79789.5 gallons, then 20 waves will use 20 * 79789.5 gallons = 1595790 gallons

3 0

3 years ago

Describe how work is done by a skater pulling in her arms during a spin. In particular, identify the force she exerts on each ar

liberstina [14]

Answer:

∑ τ =0, L₀ = $L_{f}$

Explanation:

In a circular turning movement, when the arms are extended and then contracted in two possibilities:

- They are lowered the force of gravity is what pulls them, the tension of the muscle becomes zero to allow this movement.

In this movement the force is vertical(gravity) and the movement of the center of mass of each arm is vertical, so that the work is the weight value of the arm by the distance traveled by the center of mass.

- Another possibility is that the arms have stuck to the body, in this case the person's muscles perform the force, this force is horizontal and the displacement is the horizontal of the center of mass of the arms from the extended position to the contracted

In these movements the torque of the external force is equal for each arm, but in the opposite direction, so they are canceled where a net torque of zero, this causes the angular momentum to be preserved, which changes is the moment of inertia of the system and therefore you must also change the angular velocity to keep your product constant

∑ τ =0

L₀ = $L_{f}$

I₀ w₀ = I w

4 0

3 years ago