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iragen [17]
3 years ago
9

The following initial rate data are for the reaction of tertiary butyl bromide with hydroxide ion at 55 oC:

Chemistry
1 answer:
Dafna1 [17]3 years ago
5 0

Answer:

Rate =  k [ (CH₃)₃CBr ]

k = 0.011 s⁻¹

Explanation:

The rate law in general form for this reaction is:

rate = k[A]^m x [B]^n

and we want to determine m and n.

Notice the experiments conducted involved variying the concentration of one of the reactants while keeping the other constant. By comparing two experiments in this way and noticing the effect on the reaction rate, one can deduce the order with respect to that reactant.

Take experiments 1 and 2 :

Doubling the concentration of OH⁻ while keeping (CH₃)₃CBr constant had  no effect on the initial rate.

This implies the order with respect to [OH⁻] is zero.

From experiments 1 and 3 we  see that doubling the [ (CH₃)₃CBr ] while keeping [OH-] the same doubles the initial rate.

We now have the orders of the two reactants, and the rate law will be:

rate = k [ (CH₃)₃CBr ] [ OH⁻]⁰  = k [ (CH₃)₃CBr ]

We could use another comparison to check our answer. For example comparing 3 and 4,  maintaining  [ (CH₃)₃CBr ]  constant and doubling  [ OH⁻] has no effect on the rate which confirms the order respect to  [ OH⁻]  is zero.

The rate constant we can determine it from any of the experiment by solving for k, for example from experiment 1:

7.14 x 10⁻³ M/s  = k x 0.626 M   ⇒ k = 0.011 s⁻¹

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Recall how Newton's investigation of light followed one form of scientific method​
d1i1m1o1n [39]

Observation of experiment and intervention in newton's optics. newton followed the principle of light through prisms and the rays transmitted through them as a part of his observation. Various properties of light and its characteristics were exposed.

Explanation:

  • Newton's investigation of light was based on prisms, lenses and optical rays.
  • He stated that lights differing in colour also differed in degrees of re-frangibility.
  • To support his theories newton employed "Proof by experiments" method. Each method was designated in revealing a specific property of light.
  • A phenomenon known as Newton rings were discovered by newton.
  • Newton recognized after pressing together two prisms that there was a transparent spot.
4 0
3 years ago
In the naturally occurring D series of ketoses, the carbonyl group is found on carbon number ___________, whereas in aldoses, th
Elena-2011 [213]

Answer:

second carbon atom from the  end

end carbon atom

Explanation:

Carbohydrates are naturally occurring organic compounds containing carbon, hydrogen and oxygen. The general molecular formula of Carbohydrates is C_x(H_2O)_y.

Carbohydrates can be classified based on structures,

Carbohydrates with the structure of alkanals (-CHO) are known as aldose while those of the structure of alkanones (C=O) are known as ketose.

In stereochemistry , D series is a kind of configurational arrangement where the hydroxyl group attaches itself to the right hand side.

Thus; in naturally occurring D series of ketoses, the carbonyl group is found on carbon number <u>second carbon atom from the  end </u>whereas in aldoses, the carbonyl group is found on carbon number <u> end carbon atom.</u>

7 0
3 years ago
Using the information in the table, calculate the number of moles in a \pu{7.89 kg}7.89 kg7, point, 89, space, k, g sample of as
Karolina [17]

We have to find the number of moles in a 7.89 kg sample of aspirin.

The formula of aspirin is: C₉H₈O₄

We are given the molar mass of C, H and O:

H: 1.008 g/mol C: 12.01 g/mol O: 16.00 g/mol

Since one molecule of aspirin has 9 atoms of C, 8 atoms of H and 4 atoms of O, and using the molar masses given, we can calculate the molar mass of aspirin:

molar mass of aspirin = 9 * 12.01 g/mol + 8 * 1.008 g/mol + 4 * 16.00 g/mol

molar mass of aspirin = 180.154 g/mol

Before we find the number of moles we can convert 7.89 kg to g. Since we know that there are 1000 g in 1 kg, we can convert it like this:

1000 g = 1 kg

mass of sample = 7.89 kg * 1000 g/1 kg

mass of sample = 7890 g

Finally, we can find the number of moles in the sample using the molar mass.

number of moles = 7890 g * 1 mol/180.154 g

number of moles = 43.795 moles

Answer: The number of moles in the sample is 43.8 moles (using 3 SF)

7 0
1 year ago
What is the name of CaCO2
weqwewe [10]
Calcium--Cobalt(1/2)
8 0
3 years ago
A gas occupies a volume of 67.54 liters at 158°C and 4.87 atm pressure. Calculate the number of moles of this gas.
Katarina [22]

Answer:

The number of moles of the gas is 9.295 moles or 9.30 moles

Explanation:

We use PV = nRT

Where P = 4.87 atm;

V = 67.54 L

R= 0.0821Latm/molK

T = 158 C = 158 +273 K = 431 K

the number of moles can be obtained by substituting the values in the respective columns and solve for n

n = PV / RT

n = 4.87 * 67.54 / 0.0821 * 431

n = 328.9198 / 35.3851

n = 9.295moles

The number of moles is approximately 9.30moles.

6 0
3 years ago
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