Answer:
E = 
Explanation:
For this exercise let's use Gauss's law. The Gaussian surface that follows the symmetry of the charges is a sphere
Ф = ∫ E. dA = 
the bold are vectors, the radii of the sphere and the electric field are parallel therefore the scalar product reduces to the algebraic product
Ф = ∫ E dA = \frac{x_{int} }{\epsilon_o}
E ∫ dA = \frac{x_{int} }{\epsilon_o}
E A = \frac{x_{int} }{\epsilon_o}
the area of a sphere is
A = 4π r²
the charge inside the sphere is q = + q
we substitute
E 4π r² = \frac{x }{\epsilon_o}
E =
Answer:
pressure of the water = 3.3 × 
pa
Explanation:
given data
velocity v1 = 1.5 m/s
pressure P = 400,000 Pa
inside radius r1 = 1.00 cm
pipe radius r2 = 0.5 cm
h1 = 0 (datum at inlet)
h2 = 5.0 m (datum at inlet)
density of water ρ = 1000 kg/m³
to find out
pressure of the water
solution
we consider here flow speed in bathroom that is = v2 and Pressure in bathroom is = P2
here we will use both continuity and Bernoulli equations
because here we have more than one unknown so that
v1 × A1 = v2 × A2 × P1 + ρ g h1 + (0.5)ρ v1² = P2 + ρ g h2 + (0.5) ρ v2²
now we use here first continuity equation for get v2
v2 = 
v2 = 
v2 = 6 m/s
and now we use here bernoulli eqution for find here p2 that is
P2 = P1 - 0.5× ρ ×(v2² - v1²) - ρ g (h2- h1 )
P2 = 400000 - 0.5× 1000 ×(6² - 1.5²) - 1000 × 9.81 × (5-0 )
P2 = 3.3 × pa
Answer:
volume of water inside the tank is 10 cubic meter
Explanation:
As we know that the volume of total water inside the tank is given as
here we know that
L = length = 1 m
H = height = 2 m
W = width = 5 m
now we have
So volume of water inside the tank is 10 cubic meter
Answer:
F = 5.625 10⁻⁷ N
Explanation:
For this exercise we use coulomb's law
F = 
where k is the Coulomb constant which is equal to 9 10⁺⁹ N m² /C²
as the charge on the two spheres has the same sign, the force is repulsive,
let's calculate
F = 9 10⁹ 25 10⁻⁹ 10 10⁻⁹ / 2²
F = 5.625 10⁻⁷ N
Density is (the object's mass) divided by (the object's volume).
Changing the object's shape doesn't change its mass or volume,
so its density doesn't change.
