1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
hram777 [196]
4 years ago
5

An autotransformer is used to reduce the voltage of a 100-kilovolt amp, 480-volt secondary of an isolated type transformer, to s

upply a 100-kilovolt amp load with 277 volts. What size autotransformer is needed? (Use the co-ratio to determine the size.)
Physics
1 answer:
tigry1 [53]4 years ago
5 0

Answer:

42KVA

Explanation:

Given data

High Voltage (HV)= 480V

Low Voltage (LV)= 277V

Fo find

Size of transformer=?

Solution

To find the size of transformer here we use the co-ratio.The Co-ratio is given as:

Co-Ratio= (HV - LV)/HV

where

HV is High Voltage

LV is Low Voltage

Now put the values we get

Co- Ratio=(480-277)/480=.42

So the size of transformer is 42KVA

You might be interested in
According to the exercise principle of balance, a workout should __________.
xxMikexx [17]
<span>a. address all components of fitness 

</span>According to the exercise principle of balance, a workout should address all components of fitness.
<span>NOT:
</span>b. focus on balance and coordination 
<span>c. target specific areas for improvement </span>
<span>d. vary exercise activities over time</span>

6 0
3 years ago
Read 2 more answers
What is gravitational constant?<br>​
WITCHER [35]
The constant in Newton's law of gravitation relating gravity to the masses and separation of particles, equal to 6.67 × 10-11N m2 kg-2.
6 0
3 years ago
A pilot flies in a straight path for 1 hour 30 minutes. She then makes a course correction, heading 45 degrees to the right of h
mrs_skeptik [129]

Answer:

1199 miles

Explanation:

1 hour 30 minutes = 1 + 30/60 = 1.5 hours

2 hours 15 minutes = 2 + 15/60 = 2.25 hours

The distance she flew in the 1st segment is:

1.5*345 = 517.5 miles

The distance she flew in the 2nd segment is:

2.25 * 345 = 776.25 miles

Since the 2nd segment is 45 degree with respect to the 1st segment, this means that she has flown

776.25 * cos(45) = 549 miles in-line with the 1st segment and

776.25* sin(45) = 549 miles perpendicular to the 1st segment:

So the distance from the end to her starting position is

\sqrt{(517.5 + 549)^2 + 549^2} = 1199 miles

4 0
3 years ago
Can someone tell me if I’m correct or not
Anika [276]
You are correct because nothing is being done to the cake
6 0
3 years ago
Read 2 more answers
How do scientists study pollen grains to help them understand climate change?
tino4ka555 [31]

Answer: A. by analyzing and making inferences about them

Explanation:

7 0
3 years ago
Read 2 more answers
Other questions:
  • Help I don’t understand this question
    5·1 answer
  • A solid metal can absorb heat from another object through which method of heat transfer?
    9·2 answers
  • How is thermal energy from the sun distributed on Earth ?
    12·1 answer
  • Which constellation is marked by a W or M? a. Cassiopeia b. Draco c. Ursa Minor d. Ursa Major
    15·2 answers
  • A sinusoidal electromagnetic wave is propagating in a vacuum in the +z-direction.Part AIf at a particular instant and at a certa
    14·1 answer
  • At an amusement park, a swimmer uses a water slide to enter the main pool. a. If the swimmer starts at rest, slides with negligi
    8·1 answer
  • For stars to form, the temperature of the hydrogen in a nebula must be more than 14 million Kelvin. How did gravitational attrac
    11·2 answers
  • An object has a mass of 12 kg. On Planet A, the object weighs 117.6 N. The force of gravity on Planet A is
    12·2 answers
  • A 2. 5 kg block is launched along the ground by a spring with a spring constant of 56 N/m. The spring is initially compressed 0.
    5·2 answers
  • If a 50 kg box was accelerated to 10 m/s2, how much force was used?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!