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romanna [79]
4 years ago
8

A car travels from 20-meters to 60-meters in 10 seconds. Calculate the car's speed.

Physics
1 answer:
slamgirl [31]4 years ago
3 0

Answer:

8 m/s

Explanation:

All you have to do here is add 20 and 60 (giving you 80) and dividing by 10 seconds. 80/10= 8 m/s

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A spherical wave with a wavelength of 2.0 mm is emitted from the origin. At one instant of time, the phase at rrr = 4.0 mm is πr
max2010maxim [7]

Complete Question

A spherical wave with a wavelength of 2.0 mm is emitted from the origin. At one instant of time, the phase at r_1 = 4.0 mm is π rad. At that instant, what is the phase at r_2 = 3.5 mm ? Express your answer to two significant figures and include the appropriate units.

Answer:

The phase at the second point is  \phi _2  = 1.57 \  rad

Explanation:

From the question we are told that

    The wavelength of the spherical wave is  \lambda =  2.0 \ mm =  \frac{2}{1000} = 0.002 \ m

    The first radius  is  r_1  = 4.0 \ mm  = \frac{4}{1000}  = 0.004 \ m

     The phase at that instant is  \phi _1 = \pi \ rad

     The second radius is  r_2  = 3.5 \ mm  = \frac{3.5}{1000}  = 0.0035 \ m

Generally the phase difference is mathematically represented as

          \Delta  \phi =  \phi _2 -  \phi _1

this can also be expressed as

         \Delta \phi =  \frac{2 \pi }{\lambda } (r_2 - r_1 )

So we have that

   \phi _2 -  \phi _1 =   \frac{2 \pi }{\lambda } (r_2 - r_1 )

substituting values

     \phi _2 -  \pi =   \frac{2 \pi }{0.002 } ( 0.0035 - 0.004 )

    \phi _2  =   \frac{2 \pi }{0.002 } ( 0.0035 - 0.004 ) +   3.142

   \phi _2  = 1.57 \  rad

7 0
3 years ago
Justine is ice-skating at the Lloyd Center. What is her final velocity if she accelerates at a rate of 2.0 m/s for 3.5 seconds?
belka [17]

Answer:

7 m/s

Explanation:

Acceleration, a=\frac {v-u}{t}

Where v and u are the final and initial velocities of the Justine respectively, t is the time taken for Justin to attain final velocity.

Making v the subject then

v=at+u

Taking u as zero then

Substituting 3.5 for t, 2 as a then

v=3.5*2=7 m/s

8 0
3 years ago
A construction team gives an estimate of three months to repave a large stretch of a very busy road. The government responds tha
Tasya [4]
The answer is the same as many workers needed
4 0
3 years ago
A child pulls on a wagon with a horizontal force of 75 N. If the wagon moves horizontally a total of 42 m in 1.5.0 min, what is
d1i1m1o1n [39]

Answer:

B) 35 W

Explanation:

Force applied by child =  75 N = F

Distance travelled by child = 42 m = d

Time traveled for is 1.5 min = 1.5×60 = 90 seconds = t

Work done by the child

W = Fdcosθ

⇒W = 75×42cos0

⇒W = 3150 Joule

Power is defined as work done per unit time

P=\frac{W}{t}\\\Rightarrow P=\frac{3150}{90}=35\ W

∴ The average power generated by the child is 35 W

4 0
4 years ago
How much is required to accelerate a 5kg mass at 20 m/s2
zhannawk [14.2K]

use F = ma

F : force m : mass a : acceleration

so

f = 5kg * 20 m/s2 = 100 N

5 0
3 years ago
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