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Gennadij [26K]
3 years ago
15

The nonvolatile, nonelectrolyte estrogen (estradiol), C18H24O2 (272.40 g/mol), is soluble in chloroform CHCl3.

Chemistry
1 answer:
Artist 52 [7]3 years ago
8 0

<u>Answer:</u> The molarity of solution is 0.274 M and the osmotic pressure of the solution is 6.70 atm

<u>Explanation:</u>

To calculate the molarity of the solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Given mass of estrogen = 13.5 g

Molar mass of estrogen = 272.40 g/mol

Volume of solution = 181 mL

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{13.5\times 1000}{272.40\times 181}\\\\\text{Molarity of solution}=0.274M

Hence, the molarity of solution is 0.274 M

To calculate the osmotic pressure of the solution, we use the equation:

\pi=iMRT

where,

\pi = osmotic pressure of the solution = ?

i = Van't hoff factor = 1 (for non-electrolytes)

M = molarity of solute = 0.274 M

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the solution = 298 K

Putting values in above equation, we get:

\pi=1\times 0.274mol/L\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\\pi=6.70atm

Hence, the osmotic pressure of the solution is 6.70 atm

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Answer:

286 minutes

Explanation:

Given the content of fat in a meal= 53g

the content of protien in a meal= 38g

the content of carbohydrate in a meal= 152g

Also given that fuel value of protien = 17 KJ/g

the fuel value of fat = 38 KJ/g

the fuel value of carbohydrate = 17 KJ/g

Now to burn all the molecules the energy recquired is content of molecule times the fuel value.

the energy recquired to burn fat = 53\times 38=2014KJ

the energy recquired to burn protien = 38\times 17=646KJ

the energy recquired to burn carbohydrate =152 \times 17=2584KJ

The total energy=2014+646+2584=5244KJ

The energy spent on swimming is 1100KJ/hour

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to spend 5244 KJ of energy the time taken is = \frac{5244}{1100}=4.76hours

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The total time = 4.76\times 60=286minutes

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3 years ago
how many grams of nahco3 (fm84.007) must be added ro 4.00g of k2co3 (fm 138.206) to give a ph of 10.80 in 500ml of water​
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Answer:

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Explanation:

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pH = pka + log [A⁻] / [HA]

<em>Where [HA] is concentration of acid (HCO₃⁻) and [A⁻] is concentration of conjugate acid (CO₃²⁻).</em>

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0.009570 moles ₓ (84.007g / mol) =

<h3>0.804g of NaHCO₃ you must add</h3>

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